he initial compression of the spring
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- The square-threaded screw with a pitch of 10 mm and a mean radius of 18 mm drives a gear that has a mean radius of 75 mm. The static and kinetic coefficients of friction between the gear and the screw are 0.12 and 0.06, respectively. The input torque applied to the screw is C0=10Nm. Assuming constant speed operation, determine the output torque C1 acting on the gear.Find the smallest distance d for which the hook will remain at rest when acted on by the force P. Neglect the weight of the hook, and assume that the vertical wall is frictionless.Calculate the horizontal force P required to push the 85-lb lawn mower at constant speed. The center of gravity of the mower is at G, and the coefficients of rolling resistance are 0.12 for the front wheels and 0.18 for the rear wheels.
- The arms of a Hartnell governor are of equal length. When the sleeve is in the mid- position, the masses rotate in a circle with a diameter of 150 mm (the arms are vertical in the mid-position). Neglecting friction, the equilibrium speed for this position is 360 rpm. Maximum variation of speed, taking friction into account, is to be 6% of the mid- position speed for a maximum sleeve movement of 30 mm. The sleeve mass is 5 kg and the friction at the sleeve is 35 N. Assuming that the power of the governor is sufficient to overcome the friction by 1% change of speed on each side of the mid-position, find (neglecting obliquity effect of arms), the (i) mass of each rotating ball (ii) spring stiffness (iii) initial compression of the springEach spring of a Pickering governor of a gramophone is 8mm wide and 0.15 mm thick with a length of 50 mm. A mass of 50 g is attached to each leaf spring at the centre. The distance between the spindle axis and the centre of mass when the governor is at rest is 10 mm. The ratio of the governor speed to the turntable speed is 15. Determine the speed of the turntable for a sleeve lift of 0.5 mm. Take E = 200 GPa.Each spring of a Pickering governor of a gramophone is 8mm wide and 0.15 mm thick with a length of 50 mm. A mass of 50 g is attached to each leaf spring at the centre. The distance between the spindle axis and the centre of mass when the governor is at rest is 10 mm. The ratio of the governor speed to the turntable speed is 15. Determine the speed of the turntable for a sleeve lift of 0.5 mm. Take E = 200 GPa. Select one: A. 57 rpm B. 37 rpm C. 47 rpm D. 77 rpm Clear my choice ◄ BSC105C Pre-recordedLecture Topic11 v1.2
- Consider the pulley system below in which a stack of blocks of mass m1 and m2 is being pulled by a string connected to a block of mass m3, draped over a pulley. Assume the mass of the pulley and the friction in its bearing are negligible. The string is lightweight and does not stretch. Suppose that there is no friction between block 2 and the horizontal surface. However there is friction between blocks 1 and 2 with coefficients of kinetic and static friction Hk and µs, respectively. m2 m3 Answer the following questions, following the problem-solving checklist as you present your work. 1. Assume that the three masses are such that blocks 1 and 2 do not slide relative to each other. Given m1, m2, m3, µk, and µs, find the magnitude of the friction force between blocks 1 and 2. 2. Given the friction coefficients and the masses of blocks 1 and 2, for which values of mass m3 will blocks 1 and 2 slide on each other? 3. Are there values of mị and m2 for which the two blocks will remain stuck…Ruler of the "Porter" model, with the upper and lower arms of 178 mm each, fixed by a hinge 38 mm away from the center of rotation. The rotating balls have a mass of 1.15 kg each, and the axial weight affecting the bushing is 20 kg. The ruling commotion began =154. Elevation at 280rpm - The joints are at an angle of 30 to the vertical. Assuming that the force of friction is constant, find the minimum and maximum rotational speed when mg The angle of inclination of the arms to the vertical is 45In a Porter governor, the mass of the central load is 18 kg and the mass of each ball is 2 kg. The top arms are 250 mm while the bottom arms are each 300 mm long. The friction of the sleeve is 14 N. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Calculate the range of speed of the governor.
- Q12 / A Porter governor has links 150 mm long and are attached to pivots at a radial distance of 30 mm from the vertical axis of the governor. The mass of each ball is 1.75 kg and the mass of the sleeve is 25 kg. The governor sleeve ready to rise at 300 rpm when the links are at 30 ° to the vertical. Assuming the friction force to be constant, find the value of the friction force, minimum and maximum speed of rotation when the inclination of the links is 45 ° to the vertical.012/ A Porter governor has links 150 mm lang and are allached to pivots at a radial distance of 30 mm from the vertical axis of the govermor. The mass of cach ball is 1.75 kg and the mass of the sleeve is 25 kg. The governor sleeve ready to rise at 300 rpm when the links are at 30 to the vertical. Assuming the friction force to be constant, find the value of the Inction force minimum and maximum speed of rotation when the inclination of the links is 45' to the vertical Page 14 of 15The working fluid of the small engine vehicle uses a Porter governor of equal arms of 150 mm long to control its speed. The arms are pivoted on the axis of rotation. The mass of each ball is 4 kg and the mass on the sleeve is 20 kg. The ball path is 100 mm when the governor begins to lift and 120 mm at the maximum speed. Calculate: 5.1. Minimum speed of the governor. 5.2. Maximum speed of the governor. 5.3. Range of the speed.