HCIO is a weak acid (Ka = 4.0 x 10-8) and so the salt NaCIO acts as a weak base. What is the pH of a solution that is 0.089 M in NaClO at 25 °C? pH

Q: HClO is a weak acid (Ka = 4.0 × 10–8) and so the salt NaClO acts as a weak base. What is the pH of a…

A: Ka of HClO is given as 4 x 10-8. It is required to calculate the pH of solution that is 0.054M in…

Q: Calculate the pH of a 0.0095 M solution of acetic acid, HCH3CO2,  Given Ka= 1.76x10^-5

A: Acetic acid is a weak acid so it will dissociate very less in the solution. First of all a balanced…

Q: What is the pH of a 0.122 M monoprotic acid whose K, is 5.7 x 104? a

A: question given concentration and Ka using this we can calculate the degree of dissociation  using…

Q: What is the pH of a 0.0270 M solution of hydrocyanic acid, HCN (Ka = 4.9 × 10⁻¹⁰)?

A: HCN is a weak acid , it ionizes  as follows  HCN <----> H+ + CN- Given , Concentration of HCN…

Q: When 0.075 mol of propionic acid, C2H5CO2H, is dissolved in 400 mL of water, the equilibrium…

A: The concentration of propionic acid and the ions has to be calculated in order to obtain the Ka.

Q: What is the pH of a 0.220 M solution of sodium cyanide (NaCN)? Ka for HCN is 4.9 x 10-9.

A: NaCN has one less hydrogen and corresponds to a conjugate base (a weak base). The credentials…

Q: What is the pH of a 0.232 M solution of ammonia, a weak base with a K of 1.7 x 10-5?

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: HCIO is a weak acid (Ka = 4.0 × 10-8) and so the salt NaClO acts as a weak base. What is the pH of a…

A: Kw = Ka x Kb  Kw = 1x10-14  given that Ka = 4x10-8 find Kb = (1x10-14) / (4x10-8) = 2.5x10-7 Initial…

Q: The pH of a 0.45 M solution of a weak acid, HA, is 2.13. What is the value of Ka for the weak acid?

A: Given data,pH=2.13Molarity of HA=0.45

Q: you mix 100. mL of 0.11 M HCl with 50.0 mL of 0.22 M NH3, what is the pH of the resulting solution?…

A: Volume of HCl=100.0mL Concentration of HCl=0.11M Volume of NH3=50.0mL Concentration of NH3=0.22M For…

Q: What is the pH of a 0.1055 M CH3COOH solution (Ka = 1.75 × 10−5)?

A: Given concentration of CH3COOH = 1.75 × 10-5

Q: HCIO is a weak acid (Ka 4.0 x 10-8) and so the salt NaCIO acts as a weak base. What is the pH of a…

A: Given data; Ka=4×10-8Also, Kw=Ka×KbAnd,Kw=1×10-14 Consider the dissociation of given weak acid as;…

Q: What is the pH of a 0.17 M weak acid solution? The KA of the weak acid is 2.1 x 10-5.

A: Given :-  Initial concentration of weak acid = 0.17 M  Ka for acid = 2.1 × 10-5  To be calculated :-…

Q: How many moles of NH3 must be dissolved in water to give 813.0 mL of solution with a pH of 11.15? Kb…

A: The value of Kb for the given weak base is = 1.8x10-5 The concentration of the base solution is =?…

Q: What is the pH of a 0.050 M triethylamine, (C2HS)3N, solution? Kb for triethylamine is 5.3 x 10-4

A: We should know that the amine us a basic Compound that will dissociate in solution to give basic…

Q: HClO is a weak acid (?a=4.0×10^−8) and so the salt NaClO acts as a weak base. What is the pH of a…

A: Given : Concentration of NaClO = 0.014 M Since NaClO is a weak conjugate base of weak acid HClO.…

Q: What is the PH of a 0.01 M solution of salt NaA, where A- is the anion of an acid whose ionization…

A: Given that,  Concentration of salt NaA, = 0.01 M Ionisation constant Ka   = 10-6 pH of the given…

Q: What is the equilibrium concentrations of chloroacetic acid, HC2H2O2Cl For chloroacetic acid, Ka =…

A:

Q: calculate the pH and pOH of a 4.3 x10-3M solution of NaOH

A: Concentration of NaOH = 4.3 x 10-3M NaOH is a strong base and it can dissociate into its ions…

Q: If the K, of a weak base is 3.9 x 10-6, what is the pH of a 0.48 M solution of this base?

A: Kb- is a dissociation constant of weak base. Formula is, pOH - pOH is defined as negative logarithm…

Q: HCIO is a weak acid (K, = 4.0 x 10-8) and so the salt NaCIO acts as a weak base. What is the pH of a…

A:

Q: (Q13) The poison strychnine is a weak base with Kp = 1.8 x 106. What will be the equilibrium pH of a…

A: Given-> Kb = 1.8 × 10-6 Molarity = 0.710 M

Q: A hypothetical weak base has Kb = 5.0 × 10−8. Calculate the equilibrium concentrations of the base,…

A: Given: Kb for the weak base = 5.0 × 10-8  Concentration of the weak base = 0.15 M We have to…

Q: a) What is the pH and pOH of 0.001 M NaOH solution, which is the strong base? b) The Ka value of…

A: pH + pOH = 14 pOH = -log [OH-] For a weak acid: [H+] = (Ka x C)1/2 Where, C = molar concentration

Q: 5c. What is the pH of a solution which is 0.0400 M in potassium isocyanate (K* CNO") and 0.0300 M in…

A: Given, [K+CNO-] = 0.0400 M            [HOCN] = 0.0300 M As , K+CNO- is a salt it remains as…

Q: CH;NH, is a weak base (Kp = 5.0 × 104), so the salt CH,NH,NO, acts as a weak acid. What is the pH of…

A: The pH of salt of strong acid and weak base can be calculated by  using formula

Q: What is the pH of a 0.0370 M solution of hydrocyanic acid, HCN (Ka = 4.9 × 10⁻¹⁰)?

A:

Q: What is the pH of a 0.0270 M solution of hydrocyanic acid, HCN (Ka = 4.9 × 10¬1º)?

A: Here, hydrocyanic acid is weak acid as compared to mineral acids , thus when it ionized it will form…

Q: The weak acid HXO2 has a dissociation constant of Ka = 6.50 x 10-10. A lab worker prepares of 0.600…

A: We will calculate pH

Q: Calculate the pH of a 0.05 M solution of hydrofluoric acid. The Ka of hydrofluoric acid is 6.6x10^-4

A: Given data, Molarity of HF=0.05MKa of HF=6.6×10-4 pH of a solution is given by -log[H+]

Q: Calculate the pH of a 0.383 M NH, solution. NH, has a Kp 1.8 x 10-5. pH

A: NH3 is a weak base and since Kb value is very less so it is assumed that reaction proceeds very less…

Q: Calculate the pH of a 0.100 M NaCH 3CO 2 solution. Ka for acetic acid, CH 3CO 2H, is 1.8 × 103.

A:

Q: HCIO is a weak acid (K, = 4.0 x 10-8) and so the salt NaCIO acts as a weak base. What is the pH of a…

A: given  HClO Ka=4.0 x 10-8  concentration of  NaClO IS 0.027  PH =?

Q: |Calculate the pH of a 7.2 × 10 ´ M aqueous solution of aluminum chloride, AIC13. The acid…

A: pH - pH is defined as negative logarithm to the base 10 of H+ ion concentration. Or pH can also be…

Q: When 0.040 mol of propionic acid, C2H5CO2H, is dissolved in 700 mL of water, the equilibrium…

A: Molarity is solution expressed as the number of moles of solute per litre of solution. Equilibrium…

Q: What is the pH of a solution that is 0.32 M H(C6H5COO) and 0.12 M Na(C6H5COO)?   The Ka of…

A: Answer:- This question is answered by using the simple concept of calculation of pH of solution…

Q: If the Ka of a monoprotic weak acid is 1.3 x 10-6, what is the pH of a 0.18 M solution of this acid?…

A:

Q: Calculate the pH of a solution that is 0.195M in sodium formate (NaHCO2) and 0.24 M in formic acid…

A: Given: Concentration of  sodium formate (NaHCO2) = 0.195 M            formic acid (HCO2H)  = 0.24M…

Q: What is the pH of a 0.600 M solution of HSO, (Ka = 6.6 × 10°)? (Please show your answers with 3 sig…

A: pH of solution is equal to the negative logarithm of hydronium ion concentration. pH=-log(H3O+) Ka…

Q: If the Ka of a monoprotic weak acid is 1.6 x 10-6, what is the pH of a 0.37 M solution of this acid?…

A:

Q: What is the pH of a 0.0500 M solution of hydrocyanic acid, HCN (Ka = 4.9 × 10⁻¹⁰)?

A: Given -> Molarity of HCN = 0.0500 M Ka = 4.9 × 10-10

Q: what is the ph of 0.0349 M anilinium hydrochloride (C6H5NH3CI) solution in water, given that K for…

A:

Q: HCIO is a weak acid (K. = 4.0 x 10-8) and so the salt NaCIO acts as a weak base. What is the pH of a…

A:

Q: The Ka of a weak monoprotic acid is 1.13 x 10-5. What is the pH of a 0.0777 M solution of this acid?…

A:

Q: HCIO is a weak acid (K, = 4.0 x 10-8) and so the salt NaCIO acts as a weak base. What is the pH of a…

A: pH = 7 +12 (pka + log c)

Q: The acid dissociation K, of acetic acid (HCH,Co, is 1.8 x 10 a Calculate the pH of a 2.6 x 10 M…

A: Acetic acid is a weak acid. hence it will dissociate partially as per the reaction  CH3COOH ---->…

Q: If the KbKb of a weak base is 1.6×10−6,1.6×10−6, what is the pH of a 0.18 M0.18 M solution of this…

A: Concentration of the solution is 0.18 M. Kb = 1.6 x 10-6 The Ka value is calculated by following…