H₂C O NH₂ B₂, NaOH H₂C 98 OH When an a-hydroxy amide is treated with ry in aqueous NaOH under Hofmann rearrangement conditions, loss of CO, occurs and a chain-shortened aldehyde is formed. The mechanium involves the following steps: Base abstracts an acidic amide proton, yielding amide anion The amide anion reacts with bromine in an a-substitution reaction to give N-bromoamide 2. Abstraction of the remaining amide proton by base gives a resonance-stabilized bromoamide anion Rearrangement occurs to yield isocyanate H 400, ANH, Water adds to the isocyanate to yield carbamic acid . Elimination of CD, yields carbinolamine & Following proton transfer, expubion of ammonia yields the final product aldehyde Write out the mechanism on a separate sheet of paper, and then draw the structures of carbamic acid 5 and isocyanate 4 You do not have to consider stereochemistry. You do not have to explicitly draw Hatos De not include lone pairs in your answer. They will not be considered in the grading .Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Show the correct order of synthesis by drawing a reaction arrow between the two compounds, pointing from the earlier towards the later synthewed compound 47RR 000. Air

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter23: Carbonyl Condensation Reactions
Section23.SE: Something Extra
Problem 45MP
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H₂C
0
NH₂
B₂, NaOH
98
H₂C
OH
When an a-hydroxy amide is treated with try in aqueous NaOH under Hofmann rearrangement conditions, loss of CO, occurs and a chain-shortened aldehyde is formed. The mechanhum involves the following steps:
Base abstracts an acidic amide proton, yielding amide anion
The amide anion reacts with bromine in an e-substitution reaction to give N-bromoamide 2.
Abstraction of the remaining amide proton by base gives a resonance-stabilized bromoamide anion
Rearangement occurs to yield isocyanate
Water adds to the isocyanate to yield carbamic acid
Elimination of CD, yields carbinolamine
Following proton transfer, expubion of ammonia yields the final product aldehyde
Write out the mechanism on a separate sheet of paper, and then draw the structures of carbamic acid 5 and isocyanate 4.
H 400, ANH,
You do not have to consider stereochemistry.
You do not have to explicitly draw Hatoms
De not include lone pairs in your answer. They will not be considered in the grading
.Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner,
Show the correct order of synthesis by drawing a reaction arrow between the two compounds, pointing from the earlier towards the later synthewed compound
47RR
000. Air
Transcribed Image Text:H₂C 0 NH₂ B₂, NaOH 98 H₂C OH When an a-hydroxy amide is treated with try in aqueous NaOH under Hofmann rearrangement conditions, loss of CO, occurs and a chain-shortened aldehyde is formed. The mechanhum involves the following steps: Base abstracts an acidic amide proton, yielding amide anion The amide anion reacts with bromine in an e-substitution reaction to give N-bromoamide 2. Abstraction of the remaining amide proton by base gives a resonance-stabilized bromoamide anion Rearangement occurs to yield isocyanate Water adds to the isocyanate to yield carbamic acid Elimination of CD, yields carbinolamine Following proton transfer, expubion of ammonia yields the final product aldehyde Write out the mechanism on a separate sheet of paper, and then draw the structures of carbamic acid 5 and isocyanate 4. H 400, ANH, You do not have to consider stereochemistry. You do not have to explicitly draw Hatoms De not include lone pairs in your answer. They will not be considered in the grading .Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner, Show the correct order of synthesis by drawing a reaction arrow between the two compounds, pointing from the earlier towards the later synthewed compound 47RR 000. Air
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