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- 4. One of the resonance structures of "tropylium ion" (C7H7*) is shown below. It is planar and aromatic with Hückel number of p-n electrons where n=1. Draw all the other contributing resonance structures. (There are more than two.) Based on the “average" of the contributing resonance structures, how close does the average ring carbon get to its "octeť" in tropylium ion?Methyl isocyanate, CH3 -N= C = O, is used in the industrial synthesis of a type of pesticide and herbicide known as a carbamate. As a historical note, an industrial accident in Bhopal, India, in 1984 resulted in leakage of an unknown quantity of this chemical into the air. An estimated 200,000 people were exposed to its vapors, and over 2000 of these people died. Q.) Write a Lewis structure for methyl isocyanate and predict its bond angles. What is the hybridization of its carbonyl carbon? Of its nitrogen atom?In the following Lewis structure of [(CH3)2OH]+, every atom, bond and lone pair is positioned. To complete the structure, drag the formal charge tags to the appropriate atom(s). Each marker may be used more than once, or not at all. If an atom has a formal charge of zero, do not drag a tag to it. When you drag the marker in, place the little crosshairs in the upper left corner of the marker directly over the atom(s) in question (not above them). H H-C-O-C-H HHH - H I Η Η Η 0 0 + 2+ 2-
- Compare these two structures. [0=C=N] [0=C—N: Determine whether the two represent resonance contributors of a single species or depict different substances. If two structures are not resonance contributors, explain why. Select the single best answer. O The two structures are resonance contributors of the same species. The two structures are not resonance contributors because they contain different numbers of electrons. The two structures are not resonance contributors because they contain different bond orders. O The two structures are not resonance contributors because they contain bond orders having integer values. The two structures are not resonance contributors because each structure is present in its most stable (lowest energy) configuration. The two structures are not resonance contributors because they have different arrangements of atoms. X ŚIn the following Lewis structure of [(CH3)2OH]*, every atom, bond and lone pair is positioned. To complete the structure, drag the formal charge tags to the appropriate atom(s). Each marker may be used more than once, or not at all. If an atom has a formal charge of zero, do not drag a tag to it. When you drag the marker in, place the little crosshairs in the upper left corner of the marker directly over the atom(s) in question (not above them). H. H-C Н-С-О-С-Н C-H H HH 2- II 2-A) 1) One of the following four structural formulas is not a permissible resonance contributor which one? Why? на HC на a) b) NFO c) H₂C HC H.C H₂C ks 2) Using curved arrows, show the electron movement that connects the three resonance contributors. لوج شركة السار NFO
- Other than having 4n+ 2 pi electrons, which condition(s) must be met for a molecule to be aromatic? O The molecule must be planar. The molecule must be conjugated. O The molecule must be a ring. O All of the above.If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the structure Y-X-Y could be abbreviated as XY,Z,. Classify each molecule according to its shape. Linear Bent (x 120°) Bent (x 109°) Trigonal T-shaped See-saw Square planar Square pyramidal pyramidal Answer Bank XY;Z2 XY,Z XY,Z XY,Z3 XY;Z XY,Z, XY,Z XY,Z2Draw the best Lewis structure for the linear C ion, including all lone pair electrons and non-zero formal charges.
- 3) How many electrons are delocalized in how many p-orbitals? Draw the most and second most stable resonance structures of the following compound. Order the structures by increasing stability. What is the partial charge distribution in the resonance hybrid?Rank the following in order of decreasing importance as contributing structures to the resonance hybrid of formaldehyde, H₂CO. :0: Multiple Choice I>>||| I> ||| > | #>I> | 11 E III 200a Use the VSEPR model to predict the bond angles and geometry about each highlighted atom: HH H-C-C-O-H II HH b C about C 109.5°, tetrahedral; about O 109.5°, bent about C 109.5°, tetrahedral; about O 180°, linear about C 120°, planar; about O 109.5°, tetrahedral about C 109.5°, bent; about O 180°, linear HH H-C-C-H I HH 109.5°, tetrahedral 120°, planar 180°, linear 109.5°, bent HO H-C-C-C-H H 120°, planar 109.5°, tetrahedral 109.5°, bent
