Trying to figure out the structure based on this NMR. unsat=4 so probably includes benzene ring. Unsure of how substitued the ring is. Problem 6: C₁0H15 N¹H NMR7.59.07.4Integral ratio:7.38.07.27.17.02.01 3.037.06.96.0445.04.04.013.03.02.06.012.01.00.0

Molecular formula = C10H15N Degrees of unsaturation = 4 (given) From Degree of Unsaturation compound…

¹H NMR 7.5 Problem 6: C₁0H15 N 9.0 7.4 Integral ratio: 7.3 8.0 7.2 7.1 7.0 2.01 3.03 7.0 6.9 6.0 ………… 5.0 4.0 J▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ 4.01 3.0 3.0 2.0 6.01 2.0 1.0 0.0

¹H NMR 7.5 Problem 6: C₁0H15 N 9.0 7.4 Integral ratio: 7.3 8.0 7.2 7.1 7.0 2.01 3.03 7.0 6.9 6.0 ………… 5.0 4.0 J▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ 4.01 3.0 3.0 2.0 6.01 2.0 1.0 0.0

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions

Section4.8: Stoichiometry Of Reactions In Aqueous Solution-titrations

Problem 1RC

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

100%

Trying to figure out the structure based on this NMR. unsat=4 so probably includes benzene ring. Unsure of how substitued the ring is.

Problem 6: C₁0H15 N
¹H NMR
7.5
9.0
7.4
Integral ratio:
7.3
8.0
7.2
7.1
7.0
2.01 3.03
7.0
6.9
6.0
44
5.0
4.0
4.01
3.0
3.0
2.0
6.01
2.0
1.0
0.0

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