ofilesXTabWindow Help(1).docxWorkshop Xt/takeCovalentActivity.do?locator-assignment-take1APB 11.3 Pers XSubmit AnswerWDZL Homepag XH 2ALi Be3A 4A 5A 6A 7A HeBCNO F NeS Cl ArNa Mg 38 48 58 68 78881B 28 Al Si PK Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br KrRb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I XeCs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At RnFr Ra Rc Rf Ha**NOV28Akon - B XWorkshop.docx[Review Topics]Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb LuTh Pa U Np Pu Am Cm Bk Cf Es Fm Md No LrRetry Entire Group8A(1) What is the complete ground state electron configuration for the aluminum atom?tv(2) What is the complete ground state electron configuration for the manganese atom?C From the X9 more group attempts remaining[References]Å1OWLv2 | X(6EPre

Answered: Image /qna-images/answer/9e73f275-0329-45c0-8720-2552e3e485f1.jpg

H 2A Li Be 48 BCNO F Ne Si P S Cl Ar 18 28 Al Na Mg 38 48 58 68 7888 K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Rc Rf Ha Nok Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr (1) What is the complete ground state electron configuration for the aluminum atom? (2) What is the complete ground state electron configuration for the manganese atom?

H 2A Li Be 48 BCNO F Ne Si P S Cl Ar 18 28 Al Na Mg 38 48 58 68 7888 K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Rc Rf Ha Nok Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr (1) What is the complete ground state electron configuration for the aluminum atom? (2) What is the complete ground state electron configuration for the manganese atom?

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions

Section4.8: Stoichiometry Of Reactions In Aqueous Solution-titrations

Problem 2RC

See similar textbooks

Similar questions

A My Home x O Alabama V Activity O Dashboard x G is hbr ac O (123) Ne + Assignment/takeCovalentActivity. locatoreassionment-take 身引ロ (Review Topics [References) Use the References to access important values if needed for this question. Consider the following reaction: eq 2HI(g) H,(g) + I2(g) If 1.64 moles of HI, 0.224 moles of H2, and 0.331 moles of I, are at equilibrium in a 12.9 L container at 914 K, the value of the equilibrium constant, Kp, is be eg Submit Answer Retry Entire Group 1 more group attempt remaining (Previous Next ENG 21 令口 US 5/5/20 7x Home End 8. R K
R 400m N CO₂tBu OH CO₂Me Ph LDA THF, -78 °C silica gel 6 days room temperature R MeO₂C NCO₂Bu CHO CO,Me I + H₂O
а. Cr (aq) + Cl; (9) — Сr207? (ад) + CI (аq) V b. Ni2+ (aq) + Ca(s) — Са* (аg) + Ni(s) V
N goNSU | Northeastern State Univ x * OWLV2 | Online teaching and lear X b My Questions | bartleby x + Content A east.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take Chapter 6 Homework - EOC [References) Question 5 O 1 pt Given the following data C2H4 (9) + 302(g) → 2 CO2(9) + 2H20(1) 2C2 Hs (g) + 702 (9) → 4 CO2(g) + 6H2O(1) 2H2 (g) + O2 (9) → 2H2O(1) Question 6 1 pt AH= -1411.0 kJ AH=-3119.8 kJ Question 7 O 1 pt AH=-571.7 kJ Question 8 1 pt calculate A H for the reaction Question 9 O 1 pt C2H4 (9) + H2 (g) → C,H6 (g) Question 10 O 1 pt ΔΗ= kJ Question 11 O 1 pt Question 12 O 1 pt Submit Answer Try Another Version 2 item attempts remaining Question 13 1 pt Question 14 1 pt Question 15 1 pt Question 16 1 pt Question 17 1 pt Question 18 O 1 pt Question 19 1 pt Question 20 1 pt Progress: 12/20 items Due Mar 30 at (Previous Next 11:55 PM 9:36 PM P Type here to search Hi a 99+ G 1x ENG 20 3/29/2021
Calaculate the initial concentration of [Fe3+] and [SCN-] of a solution with 5 mL of 0.002 M Fe(NO3)3, 2 mL of 0.002 M KSCN, 3 mL of water, and an absorbance of 0.221.
sid ate X OWLV2 | Onlinet X al 112021 X C Ais*war ment/takeCovalentActivity.do?locator-Dassignment-take Gmail O YouTube * Maps Attendance March... M ClassroomClipboar. RealClearMarkets 4... 国 Furnave 11:0 absorber CO2 absorber Sample When 4.766 grams of a hydrocarbon, C,H,, were burned in a combustion analysis apparatus, 14.60 grams of CO, and 6.976 grams of H,O were produced. In a separate experiment, the molar mass of the compound was found to be 86.18 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula Submit Ancwor. 4 mora nroun attemnte romaining 10:30 PM .09 10/11/2021 近0 63) ins prt sc f12 delete pue Ol4 hackcraco unu
Gold can be determined in solutions containing high concentrations of diverse ions by ICP-AES. Aliquots of 50.0 mL of the sample solution were transferred to each of four 100.0 mL volumetric flasks. A solution was prepared containing 10.0 mg/L Au in 20% H2SO4 and quantities of this solution were added to the sample solutions to give 0, 2.5, 5, and 10 mg/L added Au in each of the flasks. The solutions were made up to a total volume of 100.0 mL, mixed, and analysed by ICP-AES. The resulting data are presented in the following table. Added Au, mg/L Emission Intensity Count 12,568 19,324 26,622 40,021 0.0 2.5 5.0 10.0 Calculate the concentration of gold in the original sample.
A student measures k for a certain blue dye to be 600.4 M-¹ at 560 nm. What is the molarity of the dye in a solution with an absorbance of 0.204 at this wavelength? Ens nousior #inslo: Monia sin 8 foi 00.01 Par det id elsem. sow & netimuloa 51 (5) sonos silf et trawIm 00 001 et gauzulib im
n/ilm/takeAssignment/takeCovalentActivity.do?locator=assignment-take 20 How many grams of All3 are there in 266 grams of an aqueous solution that is 33.6 % by weight All3. g All3 4 Submit Answer R F V %6 5 T G [Review Topics] [References] Use the References to access important values if needed for this question. Retry Entire Group 9 more group attempts remaining F5 B Cengage Learning | Cengage Technical Support MacBook Air F6 6 1 Y H & 7 N U F7 J * 8 M DII FB 1 K ( 9 V DD O O L F10 P V . - 611 { [ Previous Next> + = 11 口 1 OWLVZ X Save and Exit F12 Relaunch to update 1 delete A
oricep X 3 /ilrn/takeAssignment/takeCovalentActivity.do?locator-assignment-take E Submit Answer F3 3+ 3Cu²+ (aq) + 2Cr(s) → 3Cu(s) + 2Cr³+ (aq) $ 4 R (1) [Review Topics] [References] Use the References to access important values if needed for this question. When the Cu²+ concentration is 1.20 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 1.141 v. What is the Cr³+ concentration? F4 % 5 M Retry Entire Group T DII F5 Cengage Learning Cengage Technical Support OL 6 cengag O Y C I My 8 more group attempts remaining F6 & 7 U F7 x PrtScn 8 F8 Home 9 F9 D Answer O End 0 F10 P Previous PgUp New ta X F11 A Next Save and Exit PgDn x + 9:27 PM 12/2/2022 F12
pH = 7.15 + log [0.25]/[0.50] pH = pKa + log [0.33]/[0.11]; (Ka = 6.3096 x 10-8) [OH-] = 2.78 x 10-4 % ionization of 34 relative to pKa value
g 2.png Average absorbance, .129 +0.128 +0.127)/3 = 0.128 Chrome Concentration of Females of Fe volume Q Molarity of Fe(NO₂)) = 0.2M Volume of Fe(NO₂)); = 5.00mL Moles of Fe³+= Molarity x Molarity x volume(L) Moles of Fe³* = 0.2M x 0.0054 = 10³mole 10-mole 500 x 10-3=0.002M [Fe³+] = [SCN¯] = X = ✪ [Fe³] = 0.002mol/L nknown concentrations to determine [FeSCN]at equilibrium in solution 8: Y = 4290X - 0.068 72% (0.127 + 0.068) 4290 0.127=4290X - 0.068 25ml Fe³+ x 0.002 mol/L-¹ 100mL 100% = 4.5 x 10-5mol/L 20ml SCN X 0.002 mol/L-¹ 100mL = 5.00 x 10^4 mol/L^-1 = 4.00 x 10 mol/L-1 W Flask 8 Flask 9 Flask 10 Flask 11 3.png 4.png Part 3: Q8 Flask 8 Flask 9 Flask 10 Flask 11 Part 3: 09 Flask 8 Flask 9 Flask 10 Flask 11 [Fe³+ (mol/L) 5.00 x 10-4 5.00 x 10-4 5.00 x 10-4 5.00 x 10-4 Average absorbance 0.127 0.166 0.222 69% 0.308 100% [FESCN¹ (mol/L) 4.5 x 10- 5.4 x 10 6.76 x 10-5 8.76 x 10- [SCN (mol/L) 4.00 x 10-4 4 x 10-4 7 x 10-4 1x 10-³ 3 7.png Place the results from calculations 9 and 10 into…