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Q: CAUCGGAAUAGAUCGCUAGUGGCAGGCAUAAUGAUCACCGGUCUGAGAAAAGUGGUACAUAUCAAC-5
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Given this mRNA strand: 3’ - AUGAGGAAGGUA - 5’; what are the components of the polypeptide?
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- Second letter UGU UGCCYS UCU UAU UAC Tyr UAA Stop UGA Stop A UAG Stop UGG Trp UUU Phe UUC. UCC Ser UCA UUA Leu UUG S UCG CAU CUU CUC Leu CỦA CGU CCU CC ССА CCG His CAC CGC Pro Arg CAA CGA Gln CUG CAG CGG AGU AGC AGA AAU ACU ACC ACA AUU Ser AUC File A AUA Asn AAC. AAA AAG Thr Lys AUG Met ACG AGG Arg GCU GCC GCA GCG GGU) GGC Gly GUU GUC Val G GUA GAU) Asp GAC Ala GAA Glu GAGJ GGA GUG GGG A mutation takes place during replication and the new DNA strand has the sequence 3'-ATG-5'. What is the codon on an RNA strand transcribed from this series of nucleotides? Which amino acid results from this codon? Use the genetic code to answer this question. Edit View Insert Format Tools Table 12pt Paragraph Av ev T? MacBook Pro 20 00 000 23 $ % & 7 First letter Third letter * OC 全First Second Third position (5'end) position (3' end) position U A G UAU TyrY UAC Tyr UAA Stop UAG Stop UUU Phe - F UUC Phe UCU Ser UCC Ser UCA Ser UCG Ser UGU Cys C UGC Cys UUA Leu UUG Leu UGA Stop UGG Trp W CAU His L CÁC His CGU Arg CGC Arg CUU Leu CCU Pro CỤC Leu FL CUA Leu ССС Pro - P CCA Pro CAA GIn Q CAG Gln R CGA Arg CGG Arg_ CUG Leu CCG Pro AUU lle ACU Thr AAU Asn AGU Ser ACC Thr -T ACA Thr AUC le AAC Asn. AGC Ser AAA Lys K AAG Lys AGA Arg -R AGG Arg AUA Ile AUG Met M ACG Thr GAU Asp -D GAC Asp_ GGU Gly GGC Gly GUU Val GCU Ala U GCC Ala - A GCA Ala GUC Val G GGA Gly GGG Gly - V GAA Glu -E GAG Glu GUA Val A GUG Val GCG Ala G Nonpolar Polar Basic Acidic Stop codon Table 4.1 Biology: How Life Works, Third Edition © 2019 W. H. Freeman and Company Consider this messenger RNA sequence: 5'-AUG UCG UAC ACU GCG --3' • Make a change in this sequence. Write a different version of this sequence that has nonsynonymous (missense) mutation. • Make a change in this sequence. Write a different…C A UUU U UUC Phe UCU UCC UCA UAU UAC UAA UAG UGU Cys U UGC Stop UGA Stop Stop UGG Trp G Tyr Ser UUA UUG Leu UCG CUU C CUC CUA CCU Leu ccc CCA CCG CAU CAC CAA His CGU CGC CGA CGG Pro Arg 1st Gin CUG CAG 3rd letter AUU A AUC AUA AUG ACU AAU AAC Ser u letter C Asn AGU AGC AGA AGG lle ACC Thr ACA AAA AAG Lys Arg Met ACG GUU G GUC GUA GUG GCU GCC GCA GCG GAU GAC GAA GAG Asp GGU GGC GGA GGG Val Ala Gly Glu Not all of the following ingredients are necessary for an in vitro translation reaction. Which one would you leave out? A ssDNA template O Cell sap containing ribosomes poly(U) O 14C-Phe
- C UUU UUC Phe UUA UCU) UCC UCA UAU UAC Tyr UGU UGC Cys Ser UAA Stop UGA Stop A UAG Stop UGG Trp UUG FLeu UCG CUU CUC CCU] СС CAU1 CAC САC His САА Gln CGU CGC Arg Leu Pro CUA CUG ССА CGA CUG J CCGJ Which of the following tRNA anticodons could theoretically base pair effectively with the codons 5'-AAU-3' and 5'-AAC-3' through third-base CAG, CGG AGU AAUASN AGC AUU AUC File A AUA ACU АСС АСА AAC FAsn AAA Ser C Thr AGA Arg A AUG Met ACG AAG Lys AGG GCU] GCC GCA GCG GGU GGC Gly GGA GAU1 GUU GUC GUA GUG Asp GACJ GAA C Val Ala A GAG Glu GGG wobble? 5'-GGG-3' OI. 5'-AUG-3' II. 5'-GUU-3' I. 5'-CAT-3' IV. 5'-AAA-3 V. Third letter UCAG UUAG A, First letterSecond letter UUU UUC UUA UUG. UCU UCC UCA UCG UAU Tyr UAC. Ser UAA Skp UGIA Stop UGU UGC. Phe Cys Leu UAG Sop UGG Trp CGU CGC Arg CGA CCU CAU CUU CUC CUA CUG His CAC CAA CAG Gin CCC Pro CCA Leu CCG CGG ACU AAUA AGU ]Ser AUU Asn AAC AGC AGA LArg AGG. AUC Be ACC ACA Thr AAA AUA AUG Met ACG MGys GUU GUC Val GUA GCU GCC GCA GCG Ala GAA Glu GAG GAU GAC Asp GGU GGC Gly GGA GGG GUG You come across four polynucleotide strands. The first is an original RNA strand that codes for a protein; the others are similar to the original RNA strand, except that each displays a point mutation. The point mutations are shown in red. 5' - AUG-UGC-AUU-CCU-GCA-UAA - 3' 5' - AUG-UGA-AUU-CCU-GCA-UAA - 3' 5' - AUG-UGC-AUU-CCC-GCA-UAA - 3' 5' - AUG-UGC-GUU-CCU-GCA-UAA - 3' Original RNA: Mutant RNA 1: Mutant RNA 2: Mutant RNA 3: 1. Based on how they will affect the protein product, identify the type of point mutation (missense, nonsense, silent, or frameshift) present in the Mutants 1, 2, and 3. 2. State which of…Consider the mRNA sequence below. Assume that the following mRNA segment has been translated. 5'-UACCGAAUGUCU-3' Note for numbers 1 and 2: Use the three-letter abbreviation of amino acid; separate amino acids with a hyphen: do not include the stop codon. Example: ala-cys-glu 1. Using the table of the genetic code, determine the sequence of amino acids. 2. If mutation occurs by substitution of the 12th nucleotide with cytidine-5'- monophosphate, what is the resulting amino acid sequence? 3. What type of mutation occurred? Choose from same sense, missense and non-sense.
- First base U A G U UUU UUC UUA UUG CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu Leu AUU AUC lle AUA AUG Met or start Val Second base C A UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala UAU UGU Tyr Cys UAC UGC UAA Stop UGA Stop A UAG Stop UGG Trp CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG His Gin Asn Lys Asp G Glu CGU CGC CGA CGG AGU AGC AGA AGG GGU GGC GGA GGG Arg Ser Arg Gly UCAG UCAG ט כ с AG А U ט כ C G Third base A mutation in the DNA that codes for hemoglobin changes the sequence CTC to CAC. This will cause a change in the mRNA from (original) ? to (mutated) __?____, resulting in the addition of the amino acid, (mutated) ____?___, instead of (original) ____?_3 attempts left Check my work Be sure to answer all parts. Re Consider the following sequence of DNA: 3'-AGA CCC-5'. a. What dipeptide is formed from this DNA after transcription and translation? b. If a mutation converts CCC to CCA in DNA, what dipeptide is formed? Gu c. If a mutation converts CCC to CGC in DNA, what dipeptide is formed? d. If a mutation converts CCC to GCC in DNA, what dipeptide is formed? a. b. c. d.Page 1: Second Letter C 1 2 UUU U UUC UUA Phe UCU UCC UCA UCG UAU UAC UAA UAG UGU Cys U UGC Stop UGA Stop UGG Tyr -- Ser Leu Stop A Trp G UUG CUU C CUC CCU Leu cc CAU His CGU Pro CAC CGC Arg CUA CUG CCA CCG 1st СА Gln CGA CAG CG 3rd letter AUU A AUC AUA AUG ACU ACC ACA AGU Ser AGC u letter AAU AAC AAA AAG Asn He Thr AGA AGG A Arg G Lys Met ACG GUU G GUC GUA GUG GCU GCC GAU Asp GGU GGC U Val GAC GAA GAG Ala Gly GCA GGA GGG Glu GCG 1. Convert the sequence from DNA to Amino Acids. 3-TCACCACTCTGGTCTGGTCATATCTGCCTGATATGAGTACAT - 5' a. direct transcript? b. transcript for translation? c. direction of a? (3' to 5' or 5' to 3') d. direction of a (3' to 5' or 5' to 3') e. translated peptides?
- please dont copy ur answer from chegg since the answers there on this quiestion are not correct/reliablePAYS- DASO บบบ 1 UUC UUA UUG CUU CUC CUA CUG U '} GUU GUC GUA GUG PHE LEU AUU AUC AUA AUG MET or START LEU ILE VAL UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Second base SER PRO THR ALA UAC} TYR UAA UAG } STOP CAU CAC CAA CAG} AAU AAC AAA AAG J HIS GLN ASN LYS GAU ASP GAC GAG GLU UGU CYS UGC UGA} STOP UGG TRP CGU CGC CGA CGG AGU AGC AGA AGG G GGU GGC GGA GGG ARG SER ARG GLY SCAR SCAG Аg each label into the appropriate position QRS complex Alpha wave P wave ST segment Twave Copyright McGraw-Hill Education. Permission required for reproduction or display 5 of 20 Next > S.