Given the photoelectron spectra below for phosphorus, P, and sulfur, S, which of the following best explains why the 2p peak for S is further to the left than the 2p peak for P, but the 3p peak for S is further to the right than the 3p peak for P? 135

Chemistry: The Molecular Science
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Chapter5: Electron Configurations And The Periodic Table
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Relative Number of Electrons
8. Given the photoelectron spectra below for phosphorus, P, and sulfur, S, which of the following
best explains why the 2p peak for S is further to the left than the 2p peak for P, but the 3p
peak for S is further to the right than the 3p peak for P?
Relative Number of Electrons
1000
1000
208
239
100
100
135
18.7
16.5
22.7
10
Due: Wed., 3/1/23
10
Binding Energy
1.95
2.05
1.06
1.00
1
Phosphorus
P
0.1 MJ/mol
Sulfur
S
AP Chemistry
6.1 MJ/mol
(A) S has a greater effective nuclear charge than P, and the 3p sublevel in S has greater electron
repulsions than in P.
(B) S has a greater effective nuclear charge than P, and the 3p sublevel is more heavily shielded
in S than in P.
I
(C) S has a greater number of electrons than P, so the third energy level is further from the
nucleus in S than in P.
(D) S has a greater number of electrons than P, so the Coulombic attraction between the electron
cloud and the nucleus is greater in S than in P.
Transcribed Image Text:Name: Relative Number of Electrons 8. Given the photoelectron spectra below for phosphorus, P, and sulfur, S, which of the following best explains why the 2p peak for S is further to the left than the 2p peak for P, but the 3p peak for S is further to the right than the 3p peak for P? Relative Number of Electrons 1000 1000 208 239 100 100 135 18.7 16.5 22.7 10 Due: Wed., 3/1/23 10 Binding Energy 1.95 2.05 1.06 1.00 1 Phosphorus P 0.1 MJ/mol Sulfur S AP Chemistry 6.1 MJ/mol (A) S has a greater effective nuclear charge than P, and the 3p sublevel in S has greater electron repulsions than in P. (B) S has a greater effective nuclear charge than P, and the 3p sublevel is more heavily shielded in S than in P. I (C) S has a greater number of electrons than P, so the third energy level is further from the nucleus in S than in P. (D) S has a greater number of electrons than P, so the Coulombic attraction between the electron cloud and the nucleus is greater in S than in P.
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