Given the network 192.168.12.0/24, using VLSM that meets the following requirements: One subnet of 60 hosts for the Marketing VLAN One subnet of 80 hosts for the Sales VLAN One subnet of 20 hosts for the Admin VLAN One 2-host s
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VLSM Exercise
Given the network 192.168.12.0/24, using VLSM that meets the following requirements:
One subnet of 60 hosts for the Marketing VLAN
One subnet of 80 hosts for the Sales VLAN
One subnet of 20 hosts for the Admin VLAN
One 2-host subnet to be assigned to router links
Step by step
Solved in 4 steps
- Subnetting Complete the given tables below: # of Subnets # of hosts per subnet Network Address of the first subnet Network Address of the last subnet Subnet Mask 1. 101.138.121.114 /22 --> /25 2. 221.17.27.41 /24 ---> /26 3. 65.120.65.162 /18 ---> 20 #hosts Subnet Mask in Binary Subnet Mask in Decimal Prefix 35 1289 130Refer the exhibit and the required number of hosts given. Subnet the address 192.168.50.0/24 for the required number of hosts using VLSM and complete the subnet table using the following instructions: NW: 192.168.50.0/24 NET-X: 45 USABLE HOSTS NET-Z: 2 USABLE HOSTS NET-Y: 25 USABLE HOSTS ------ GO/O R2 G0/0 GO/1 GO/1 R1 PC2 PC1 Assign the first subnet to network with the highest host requirement. Assign the second subnet to the network with the second highest host requirement. Assign the third subnet to the network with the third highest host requirement. Subnet Table: Subnet No. of Subnet First Last Usable Broadcast Subnet Name Usable Address Usable Host Address Mask hosts Host Address required AddressComplete the given tables below: # of Subnets # of hosts per subnet Network Address of the first subnet Network Address of the last subnet Subnet Mask 1. 101.138.121.114 /22 --> /25 2. 221.17.27.41 /24 ---> /26 3. 65.120.65.162 /18 ---> 20 #hosts Subnet Mask in Binary Subnet Mask in Decimal Prefix 35 1289 130
- VLSM between Routers 1 – 6• The address 190.170.1.0/24 has been subnetted to /27• You will use the 2nd range for your VLSM calculations190.170.1.32 ~ 190.170.1.63• This address will be subnetted so there are 2 usable addresses persubnet• The following is how you are to apply the addresses:o Router1 – Router2 will use the 3rd rangeo Router2 – Router3 will use the 4th rangeo Router3 – Router4 will use the 5th rangeo Router4 – Router5 will use the 6th rangeo Router5 – Router6 will use the 7th rangeSubnets used: For the LAN addresses, you must use the classful network space 192.168.13.0. Use the VLSM design guidelines to subnet that classful network between R1, R2, and R3 based on the following requirements: R1 needs to support 29 hosts R2 needs to support 56 hosts R3 needs to support 11 hostsA router interconnects a subnet, where all the interfaces of the subnets must have the prefix 164.132.62/24. suppose that the Subnet is required to support up to 60 interfaces, provide a network address that satisfies the above.
- Design a classfull network addressing scheme that will supply the minimum number of hosts per subnet, and allow enough extra subnets and hosts for 25% growth in all areas. IP Address 172.16.0.0 FO/0 S/0/1 FO/O Sales Administrative Router A FO/1 SO/0/0 185 Hosts 30 Hosts Marketing 50 HostssWin an international IT solutions company, is launching 11 new branches in a new country where they currently have no existing branches. The sWin CIO has asked that each subnet should host at least 2000 devices. sWin has obtained a network address of 10.11.0.0/17.This address needs to be subnetted further and the CIO has decided that the internal subnet mask will be /21 The company’s subnet plan allows for: Router Pool: 2 router interfaces for each subnet – the last 2 IP addresses from each subnet. Managed Network Device Pool: The first 64 IP addresses are reserved for switches and other network devices Server Pool: The first 64 IP addresses following the Managed Network Device Pool are reserved for servers. Workstation Static Pool: The first 16 IP addresses following the Server Pool are reserved for Workstations that require static IP addresses. Workstation DHCP Pool: The remaining IP addresses are reserved for automatic IP configuration. You have been asked to use subnet 10 for…19. ARP is used for: O packet path determination O finding of a mapping IPV6 → MAC address O finding of a mapping IPV4 → MAC address O finding of a mapping IPV4 → TCP address
- 1. A router receives a packet with destination address (222.186.114.16) Show how it finds the network and the subnetwork address to route the packet. Assume the number of subnetwork required is four7.1 In IEEE 802.11, open system authentication is accomplished via a simple two-way communication. The client requests authentication, which includes the station ID, which is provided by the server (typically the MAC address). A successful or unsuccessful authentication response from the AP/router is received in response to the previous request from the client. For instance, if the client's MAC address has been expressly omitted from the AP/router setup, a failure may occur.a. What are the advantages of using this kind of authentication scheme?b. What are the security flaws in this authentication method and how may they be mitigated?MC9: In wireless LAN communication, MACA is widely used. In this protocol, in order to avoid collision, a sender can send sender is granted the privilege to send a frame to the receiver only after it receives request signal to a receiver. The replied from the receiver. RTS, RTS CTS, CTS RTS, CTS CTS, RTS