Given the initial values of the registers, fill in the new values after executing the following assembly instructions right before the bold line. Write down your answer in hexadecimal with leading 0x.   0x555555555261: call 0x5555555546fa 0x555555555267: add $2, %rax ... 0x5555555546fa: push %rax 0x5555555546fe: lea -0x8(%rbp), %rbx 0x555555554705: leave     Register values   Register name Initial value New value %rip 0x0000555555555261 Blank 1 %rsp 0x00000000000fff90 Blank 2 %rbp 0x00000000000fff98 Blank 3 %rax 0xf0f0f0f0f0f0f0f0 Blank 4 %rbx 0x0f0f0f0f0f0f0f0f Blank 5   Stack values (the memory has initial values of zero 0x0000000000000000)   Memory address Initial value New value 0xfff80 0x0000000000000000 Blank 6 0xfff88 0x0000000000000000 Blank 7 0xfff90 0x0000000000000000 Blank 8       Blank 1  YOUR ANSWER=  Blank 2  YOUR ANSWER=  Blank 3  YOUR ANSWER=  Blank 4  YOUR ANSWER=  Blank 5  YOUR ANSWER=  Blank 6  YOUR ANSWER=  Blank 7  YOUR ANSWER=  Blank 8  YOUR ANSWER=  PLEASE EXPLAIN THIS QUESTION AND EXPLAIN THE ANSWERS AS WELL

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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  1. Given the initial values of the registers, fill in the new values after executing the following assembly instructions right before the bold line. Write down your answer in hexadecimal with leading 0x.

     

    0x555555555261: call 0x5555555546fa

    0x555555555267: add $2, %rax

    ...

    0x5555555546fa: push %rax

    0x5555555546fe: lea -0x8(%rbp), %rbx

    0x555555554705: leave

     

     

    Register values

     

    Register name

    Initial value

    New value

    %rip

    0x0000555555555261

    Blank 1

    %rsp

    0x00000000000fff90

    Blank 2

    %rbp

    0x00000000000fff98

    Blank 3

    %rax

    0xf0f0f0f0f0f0f0f0

    Blank 4

    %rbx

    0x0f0f0f0f0f0f0f0f

    Blank 5

     

    Stack values (the memory has initial values of zero 0x0000000000000000)

     

    Memory address

    Initial value

    New value

    0xfff80

    0x0000000000000000

    Blank 6

    0xfff88

    0x0000000000000000

    Blank 7

    0xfff90

    0x0000000000000000

    Blank 8

     

     

     
    • Blank 1  YOUR ANSWER= 
    • Blank 2  YOUR ANSWER= 
    • Blank 3  YOUR ANSWER= 
    • Blank 4  YOUR ANSWER= 
    • Blank 5  YOUR ANSWER= 
    • Blank 6  YOUR ANSWER= 
    • Blank 7  YOUR ANSWER= 
    • Blank 8  YOUR ANSWER= 

    PLEASE EXPLAIN THIS QUESTION AND EXPLAIN THE ANSWERS AS WELL

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