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Given the information below, write the equilibrium expression for the reaction. Reaction C₂H5OH + 3 O₂ = Initial Change Final K= 2 (2-x)(2-3x)³ (2x)² (3x)³ 2 2 CO₂ 0 + 3 H₂O 0

Given the information below, write the equilibrium expression for the reaction. Reaction C₂H5OH + 3 O₂ = Initial Change Final K= 2 (2-x)(2-3x)³ (2x)² (3x)³ 2 2 CO₂ 0 + 3 H₂O 0

Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.40P: 7-40 Is there any change in conditions that change the equilibrium constant, K, of a given reaction?
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Given the information below, write the equilibrium expression for the reaction. Reaction C₂H5OH + 3 0₂ = Initial Change Final K= K= K= K= 2 (2-x)(2-3x)³ (2x)² (3x)³ (2x)(3x) (2-x)(2-3x) (x)²(x)³ (2-x)(2-x)³ (2x)² (3x)³ (2-x)(2-3x)³ 2 2 CO2 0 + 3 H₂O 0
Transcribed Image Text:Given the information below, write the equilibrium expression for the reaction. Reaction C₂H5OH + 3 0₂ = Initial Change Final K= K= K= K= 2 (2-x)(2-3x)³ (2x)² (3x)³ (2x)(3x) (2-x)(2-3x) (x)²(x)³ (2-x)(2-x)³ (2x)² (3x)³ (2-x)(2-3x)³ 2 2 CO2 0 + 3 H₂O 0
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