Given string userInput, output "Found match" if the first character of userInput is 'w'. Otherwise, output "No match". End with a newline. Ex: If the input is: warmth then the output is: Found match Note: Assume the length of strin
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Control structures
Control structures are block of statements that analyze the value of variables and determine the flow of execution based on those values. When a program is running, the CPU executes the code line by line. After sometime, the program reaches the point where it has to make a decision on whether it has to go to another part of the code or repeat execution of certain part of the code. These results affect the flow of the program's code and these are called control structures.
Switch Statement
The switch statement is a key feature that is used by the programmers a lot in the world of programming and coding, as well as in information technology in general. The switch statement is a selection control mechanism that allows the variable value to change the order of the individual statements in the software execution via search.
Given string userInput, output "Found match" if the first character of userInput is 'w'. Otherwise, output "No match". End with a newline.
Ex: If the input is:
warmth
then the output is:
Found match
Note: Assume the length of strin
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- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current stringThe countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));…Given string stringVal on one line, integer idxStart on a second line, and integer choiceLen on a third line, replace choiceLen characters with "1234", starting at index idxStart. Ex: If the input is: Fuzzy bear 3 4 then the output is: Fuz1234ear Note: Using a pre-defined string function, the solution can be just one line of code. #include <iostream>#include <string>using namespace std; int main() { string stringVal; int idxStart; int choiceLen; getline(cin, stringVal); cin >> idxStart; cin >> choiceLen; /* Your code goes here */ cout << stringVal << endl; return 0;}
- Ex: Use getline() to get a line of user input into a string. Output the line. Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. Search the string (using find()) for common abbreviations and print a list of each found abbreviation along with its decoded meaning. Ex: Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. BFF: best friend forever IDK: I don't know Support these abbreviations: BFF -- best friend forever IDK -- I don't know . JK -- just kidding TMI -- too much information TTYL-talk to you later 1 #include 2 // FIXME include the string Library 3 using namespace std; 4 5 int main() { 6 7 8 9 10 } /* Type your code here. */ return 0; main.cppGiven a string on one line and an integer number on a second line, add a copy of the last number of characters of the string to the string's end. Then, output the result. Ex: If the input is: Fuzzy bear 4 the output is: Fuzzy bearbear Note: Using a pre-defined string function, the solution can be just one line of code. #include <iostream>#include <string>using namespace std; int main() { string strVar; int substrLen; getline(cin, strVar); cin >> substrLen; /* Your code goes here */ cout << strVar << endl; return 0;}Given string inputString on one line, character userChar on a second line, and integer strIndex on a third line, output "Match found" if the character at index strindex of inputString matches userChar. Otherwise, output "Match not found". End with a newline. Ex: If the input is: write i 2 then the output is: Match found Note: Assume the length of string inputString is greater than strIndex. 1 import java.util.Scanner; 2 3 public class Matching Char { 4 5 7 8 9 10 11 12 13 14 15 16 public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String inputString; char userChar; int strIndex; 3 inputString = scnr.nextLine(); userChar scnr.next().charAt(0); strIndex scnr.nextInt(); *Your code goes here */
- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…Write a program called palindrome.cpp. The program should have the two functions listed below. Your program should loop until the user enters “quit". The determination of a word being a palindrome or not should be case insensitive. void getWord ( string& word ): This function is responsible for getting the word from the user. void isPalindrome ( string& word, bool& result ): This function is responsible for determining if a word is a palindrome or not. It will return true if the word is a palindrome and false if the word is not a palindrome using a boolean variable passed by reference. Sample Output 1 What is the word? Kayak Kayak is a palindrome Sample Output 2 What is the word? APPLE APPLE is not a palindrome Notes • Remember that you can access each character in a string by using the index operator, i.e., word[3], and the highest index of any string is the length of the string minus one. • To handle the case-insensitivity part you may need to work with functions that change the case…
- Given 2 strings, return their concatenation, except remove the last character of each and swap the order of the inputted words. The strings will be at least length 3. Ex: If the input is: bird penguin the output is: pengiubir Ex: If the input is: loving csce the output is: csclovinIn Python, The function add_char_counts takes three parameters: a string s and two strings of length 1, char1 and char2, and returns the total number of times either char1 or char2 appears in s. For example, the word "scallions" has 2 s's and 1 n, so add_char_counts("scallions", "s", "n") returns 3. Hint: Use a string method to help solve this problem (count). You do not need an accumulator. For example: Test Result print(add_char_counts('Indiana', 'a', 'b')) 2 print(add_char_counts('BAHAMAS', 'A', 'B')) 4 print(add_char_counts('Mississippi', 'i', 'M')) 5 print(add_char_counts("spam spam spam spam", "s", "p")) 8Language :Python write a program that asks the user to enter a series of single digit numbers with nothing seperating them. The program should display the sum of all the single digit numbers in the string. For example, if the user enters 2514 the method should return 12, which is hw sum of 2,5,1 and 4. write a program that reads a string from the user containing a date in the form mm/dd/yy. it should print the date in the format March 12, 2018.