Given: (L, H, F) = (4.00, 4.75, 10.00) • L = 4.00 m • H = 4.75 m • F = 10.00 Newtons A B D - DT <―DT DG BEG E C F Find: ⚫ the magnitude of the force in member DT = Newtons

Identify the zero-force-members in the frame shown in Figure 1.4. / Identifiseer die nulkrag elemente van die raamwerk wat in Figuur 1.4 getoon word. F zero non-zero non-zero zero non-zero non-zero A B όσο Figure 1.4/Figuur 1.4 zero non-zero E.

Problem 5 Determine the magnitudes of the components of the force acting along the axis AB of the wrench handle and perpendicular to it. Son Can toa 300 mm x B 9 = 128° (0,0,300) 500 mm UF = COS 30%. Sin us i = -0.6124; + 0.6124j F = 80 N 30 5 45" + Cos 30° cos 45j+ sin 30 + 0.5k (0,500, 300) UAB = -j Cos 0 = UF • UAB = (-.61241 - 0.61245 +95 k) (-j) I How do we go from this = -0.6124 to this?

Determine the magnitude and direction of each force. In the figure shown, a = 8 in and F= 100 lbf. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. = -10 in- B -10 in- -10 in F C What are the values of the x and y forces at point O in lbf? Rox lbf lbf Roy

LTE .. bö In the Figure 6, the absolute force value in the bar AC is (in kN): Figure 6: у 5 m 5 m X A 20 kN 5 m ۱۱:۳۲ 2:27:29 B السؤال الاختيارات 25 O 21 O 19 23 O ( O

F- (10 53.13 F2=200 ·$ B IM F1=150 F2=50

P1=170 P2=17

Answer for the 1st part of the problem.   magnitude of force A = 74 N direction of force A = 25o north of west second force = P direction of force P = α south of west arrow_forward The resultant of two forces is horizontal , it means that the y component of resultant = 0 Ry = ASin(25o) - PSin(α) 0 = (74×0.42) - PSin(α) PSin(α) = 31.08 NFor, the smallest force P , the value of Sinα must be maximum which is 1 when the value of αis 90 degree Thus, P×Sin(90o) = 31.08 N P = 31.08 N The magnitude of smallest force P = 31.08 N the direction of force P = 90 degree south of west = along - y axis= arrow pointing vertically downw

3 degree indeterminate Replace both 10KN with 101 KN

Given the 600-N force applied to the bracket at A in Fig 1, determine: