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- Atomic weights are not provided, but please use rounded-off values to the nearest whole number.(examples: 24.305, use "24"; 107.8682, use "108"; 1.00784, use "1"; 15.999, use "16") Final answer in 3 decimal places 1. A fat sample with combination free fatty acids required 8mL and 5mL of standard hydrochloric acid for blank and sample titration, respectively. The normality of the standard hydrochloric acid is 0.93N and the weight of the sample is 3 grams. Calculate the saponification value. 2. A 500mg oil sample is taken from a conical flask and is dissolved in 50mL distilled alcohol. An indicator is added and is then titrated against 0.112N KOH until a slight pink color appears. It took 17.6mL of the titrant to reach the endpoint. What is the sample’s Acid Value?Below is the procedure described for determination of paracetamol according to BP: "Weigh and powder 20 tablets. Add a quantity of powder equivalent to about 0.35 g paracetamol to 50 ml of 0.1 M NaOH, dilute with water to 200 ml and shake for 15 min. Add sufficient water to make up 250 ml. Filter the solution and dilute 5 ml of the filtrate to 100 ml with water. Dilute further 10 ml to 100 ml. Measure the absorbance at 257 nm. The A," following is correct? 715 at 257 nm". Which of the O a. An analyst can take 0.37g of the powdered tablets instead of 0.35. O b. An analyst can replace NaOH with HCI OC. An analyst can skip the shaking step O d. B andC O e. All of the aboveBelow is the procedure described for determination of paracetamol according to BP: "Weigh and powder 20 tablets. Add a quantity of powder equivalent to about 0.35 g paracetamol to 50 ml of 0.1 M NaOH, dilute with water to 200 ml and shake for 15 min. Add sufficient water to make up 250 ml. Filter the solution and dilute 5 ml of the filtrate to 100 ml with water. Dilute further 10 ml to 100 ml. Measure the absorbance at 257 nm. The A = 715 at 257 nm". Which of the following is correct? O a. An analyst can take 0.37g of the powdered tablets instead of 0.35. O b. An analyst can replace NAOH with HCI C. An analyst can skip the shaking step d. B and C e. All of the above
- Gas chromatography requires a sample size. O Much, much less than a gram A gram or less 1 to 10 grams 10 to 100 grams Gas chromatography does not have a restriction on its sample size QUESTION 11 Which of the following would not have a characteristic functional group absorption in an IR spectrum? butanal benzoic acid O dimethyl ether O propanone O 1-pentanol QUESTION 12 All of the following except for is a required step in ion-exchange chromatography. The packed column is equilibrated with a buffer. O Determination of the distance traveled by the analyte. O The column is washed with additional buffer to remove unbound components. O The elution of the bound analyte. O The sample is loaded onto the column.Below is the procedure described for determination of paracetamol according to BP: "Weigh and powder 20 tablets. Add a quantity of powder equivalent to about 0.35 g paracetamol to 50 ml of 0.1 M NaOH, dilute with water to 200 ml and shake for 15 min. Add sufficient water to make up 250 ml. Filter the solution and dilute 5 ml of the filtrate to 100 ml with water. Dilute further 10 ml to 100 ml. Measure the absorbance at 257 nm. The A, = 715 at 257 nm". Which of the following is correct? O a. An analyst can take 0.37g of the powdered tablets instead of 0.35. O b. An analyst can replace NaOH with HCl O c. An analyst can skip the shaking step O d. B andC O e. All of the aboveTom, an analytical chemist, bought a bag of decaffeinated coffee from a grocery store. However,Tom suspected that he might have received regular coffee and therefore decided to analyze hiscoffee for caffeine. In the lab, he took 0.5 mL of the brewed coffee and diluted it in water tomake a 100.0 mL solution. He performed four analyses and found the concentrations to be 4.69,3.99, 4.12, and 4.50 mg/L, respectively. (Assume the density of all solutions is 1.000 g/mL,1oz= 28.35 mL).(a) Report the concentration (in mg/L) of caffeine in the brewed coffee using the format asaverage ± standard deviation. (Note this is not the concentration in the diluted solution.)(b) Look up the caffeine content of regular vs. decaffeinated coffee. Do you think that Tom wasgiven the wrong type of coffee?(c) Caffeine intake of 300 mg per day reportedly has no adverse effects in the vast majority ofthe adult population. If Tom drinks 3 cups (8 oz/cup) of this coffee daily, is his intake withinthis known safe…
- The surface of the silica gel has a structure that looks like this diagram below. Suppose you used a plate coated with silica gel, with propanone, CH3COCH3, as the solvent for thin-layer chromatography. Sno Suppose also that the mixture you were trying to identify contained • benzaldehyde •benzanilide • phenol 1) rank the Rf Value from large to small 2) name the IMF between each compound and the silica gel OH OH main body of silica structureDuring an assay of paracetamol by UV an analyst prepares a series of calibration solutions containing approximately 3-15 mcg/mL paracetamol as follows: 140.1 mg of pure paracetamol was added to a 200 mL volumetric flask. 0.1 M NaOH (50 mL) was added, the mixture well shaken and made up to volume with deionized water 10 mL of the above solution was diluted to 100 mL 1)What is the concentration of the final diluted solution in mcg/mL?(1 decimal) 2) What volume of the diluted solution is required to prepare 100 mL of a 8 mcg/mL standard solution? (1 decimal). Given the following drugs in a urine specimen: Cocaine alkaloid Secobarbital (a derivative of barbituric acid) Carisoprodol (a neutral drug) Devise an analytical flow chart that will be used to separate these substances from a urine specimen. The separation will be liquid extraction methods. Choose appropriate solvents and reagents based on the properties of the materials to be separated.
- Upon screening with TLC (made of silica gel) chromatography using hexane/chloroform (3:1) as eluting solution, 3 spots were detected corresponding to a (A) polyphenol, a (B) tannin and an (C) alkaloid. Write the letters of your answers on the spots in the chromatogram shown at the right.A 50.0 mL juice extract is colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of the solution and the standard glucose solution (concentration: 1mg/mL) were treated with freshly prepared Nelson’s reagent and arsenomolybdate reagent and then diluted to 10.0 mL separately in properly labeled test tubes. Absorbance at 480 nm for the standard is 1.702 and for the sample, 0.926. A. What is the principle behind the assay?A 50.0 mL juice extract is colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of the solution and the standard glucose solution (concentration: 1mg/mL) were treated with freshly prepared Nelson’s reagent and arsenomolybdate reagent and then diluted to 10.0 mL separately in properly labeled test tubes. Absorbance at 480 nm for the standard is 1.702 and for the sample, 0.926. Calculate the concentration of the reducing sugar in the 50.0 mL sample in mg/mL. Apply Beer-Lambert’s law: A=bc.