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- Find the area between the curves in Exercises 1-28. x=0, x=/4, y=sec2x, y=sin2xAn integral expression for the area of the surface generated by rotating the curve X =Vv, 1sys8 about the x-axis is S 2 TX°Vdx 1+ 3x* 2 TTX .2 2 TIXV1+ 3x2 dx S, 2 nx*V1+ 9x*dx 3 2 TXV1+9x2 dxUse quadrilateral JKLO. yK -2 0 -2 !3D What are the coordinates of the image R(90 o)(JKLO) = J'K'L'O'? J = ( K' = ( L' ( O = ( Review pro 2.
- Use Green's Theorem to evaluate the line integral. Assume the curve is oriented counterclockwise. (ox+ e*)ay-y² + cos dx, where C is the boundary of the square with vertices (4, 3), (7, 3), (7, 6), and (4, 6). dy - dy 9y + cos dx =Convert this integral from rectangular coordinates to cylindrical coordinates (Do not evaluate the integral) √1-y² xzdzdxdy.