3eqreqFor the reactionN₂ (9)+ 3H2(g) → 2NH3 (9)AH = -92.2 kJ and AS = -199 J/KThe equilibrium constant for this reaction at 256.0 K isAssume that AH and AS are independent of temperature.Submit Answer$RReferences to access important values if needed for this question.Retry Entire Group 9 more group attempts remainingShow HintCengage Learning | Cengage Technical Support7ZU*81M(KOLPrevious Next>Save an5

Given -> N2(g) + 3H2(g) --->2NH3(g) ∆H° = -92.2 KJ = -92200 J (1KJ = 1000 J) ∆S° = -199 J/K…

For the reaction to access important values if needed for N₂ (9) + 3H₂(g) → 2NH3 (9) AH = -92.2 kJ and AS = -199 J/K The equilibrium constant for this reaction at 256.0 K is Assume that AH and AS are independent of temperature. Submit Answer Retry Entire Group 9 more group attempts remaining

For the reaction to access important values if needed for N₂ (9) + 3H₂(g) → 2NH3 (9) AH = -92.2 kJ and AS = -199 J/K The equilibrium constant for this reaction at 256.0 K is Assume that AH and AS are independent of temperature. Submit Answer Retry Entire Group 9 more group attempts remaining

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter17: Chemcial Thermodynamics

Section: Chapter Questions

Problem 17.20QE: The equilibrium constant for a reaction decreases as temperature increases. Explain how this...

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3
eq
req
For the reaction
N₂ (9)+ 3H2(g) → 2NH3 (9)
AH = -92.2 kJ and AS = -199 J/K
The equilibrium constant for this reaction at 256.0 K is
Assume that AH and AS are independent of temperature.
Submit Answer
$
R
References to access important values if needed for this question.
Retry Entire Group 9 more group attempts remaining
Show Hint
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