For the power system below, find the average power for each of the loads, the average power for the system, the reactive power, and the power factor. Voltage is in RMS. + 440 V, 60 Hz 124/0° Ω (20 – j25) Ω (80 + j60) Ω

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.11MCQ: The power factor for an inductive circuit (R-L load), in which the current lags the voltage, is said...
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For the power system below, find the average power for each of the loads, the average power for the system, the reactive power, and the power factor. Voltage is in
RMS.
+
440 V, 60 Hz
124/0° Ω
(20 – j25) Ω
(80 + j60) Ω
Transcribed Image Text:For the power system below, find the average power for each of the loads, the average power for the system, the reactive power, and the power factor. Voltage is in RMS. + 440 V, 60 Hz 124/0° Ω (20 – j25) Ω (80 + j60) Ω
S for 124 < Odeg: 3.7776 kW -j4.7219 KVAR
S for 124 < Odeg: 1.56129 kW
S for 124 < Odeg: 1.5488 kW +j1.1616 KVAR
S for 124 < Odeg: 3.7776 kW
S for 20-j25 ohm: 3.7776 kW - j4.7219 KVAR
S
for 20-j25 ohm: 1.56129 kW
S for 20 - j25 ohm: 1.5488 kW + j1.1616 kVAR
S
for 20-j25 ohm: 3.7776 kW
S for 80-j60 ohm: 3.7776 kW - j4.7219 KVAR
S for 80-j60 ohm: 1.56129 kW
S for 80 - j60 ohm: 1.5488 kW +j1.1616 KVAR
S for 80 - j60 ohm: 3.7776 kW
S total = 9.1024 kW - j3.56 kVAR
S total = 9.1024 kW - j9.4438 KVAR
S total = 6.888 kW - j3.56 kVAR
S total = 6.888 kW -j9.4438 kVAR
Q total = -9.4438 KVAR
Q total = -3.56 kVAR
Q total = 9.1024 kW
Q total = 6.888 kW
pf = 0.95
pf = 0.79
pf = 0.89
pf = 0.34
Transcribed Image Text:S for 124 < Odeg: 3.7776 kW -j4.7219 KVAR S for 124 < Odeg: 1.56129 kW S for 124 < Odeg: 1.5488 kW +j1.1616 KVAR S for 124 < Odeg: 3.7776 kW S for 20-j25 ohm: 3.7776 kW - j4.7219 KVAR S for 20-j25 ohm: 1.56129 kW S for 20 - j25 ohm: 1.5488 kW + j1.1616 kVAR S for 20-j25 ohm: 3.7776 kW S for 80-j60 ohm: 3.7776 kW - j4.7219 KVAR S for 80-j60 ohm: 1.56129 kW S for 80 - j60 ohm: 1.5488 kW +j1.1616 KVAR S for 80 - j60 ohm: 3.7776 kW S total = 9.1024 kW - j3.56 kVAR S total = 9.1024 kW - j9.4438 KVAR S total = 6.888 kW - j3.56 kVAR S total = 6.888 kW -j9.4438 kVAR Q total = -9.4438 KVAR Q total = -3.56 kVAR Q total = 9.1024 kW Q total = 6.888 kW pf = 0.95 pf = 0.79 pf = 0.89 pf = 0.34
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