For the galvanic (voltaic) cell Fe(s) + Mn2*(aq) – Fe2*(aq) + Mn(s) (E° = 0.77 V at 25°C), what is [Fe2*] if [Mn2*] = 0.080 %3D M and E = 0.78 V? Assume T is 298 K

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Chapter19: Electrochemistry
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Problem 19.71QP: What is the standard cell potential you would obtain from a cell at 25C using an electrode in which...
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For the galvanic (voltaic) cell
Fe(s) + Mn²*(aq) – Fe2* (aq) +
Mn(s) (E° = 0.77 V at 25°C),
what is [Fe2*] if [Mn²*] = 0.080
M and E = 0.78 V? Assume T
is 298 K
Transcribed Image Text:For the galvanic (voltaic) cell Fe(s) + Mn²*(aq) – Fe2* (aq) + Mn(s) (E° = 0.77 V at 25°C), what is [Fe2*] if [Mn²*] = 0.080 M and E = 0.78 V? Assume T is 298 K
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