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- A single phase full wave AC voltage controller has a resistive load of 5 ohms and an input voltage of Vs = 220 V (RMS), 50 Hz. The delay angles of both thyristors are set to 90 degrees. The maximum power that can be delivered to the load is: Select one: a. 5.65 kW b. 9.68 kW c. 11.52 kW d. None of theseAn AC circuit is shown in the diagram. The source of emf has a peak voltage of 9.00 V and a frequency of 60.0 Hz. Assume the wires contribute a negligible amount to the resistance and the AC source has negligible internal resistance. 524 2 493 2 1.56 k2 a) Find the equivalent resistance of the circuit. Redraw the circuit showing the equivalent resistor and use this simplified circuit for the rest of the problem. 315 2 Re = b) Find the rms current. 9.00 V, 60.0 Hz c) If the current is zero at time t= 0, find the first two times (after time t-0) that the current is equal to its rms value. and d) Find the average power dissipated by the circuit.A DC line has a resistance of 0.8 ohms. A load of 10 KW is taken at far end, while at the midpoint a current at 14 ampere at 204 volt is taken.Please find the supply voltage.
- The armature and field resistances of a series machine are 0.2 ohm and 0.3 ohms respectively. While running as a generator, the generated emf is 250V at 1200rpm. If the machine is run as motor, it takes 4A at220V. At a certain load, the motor takes 30A at 220V. However, on load, the armature reaction weakens the field by 4%. Find the motor speed at this load.The induced emf in a dc machine when running at 500 rpm is 180 v. calculate he induced emf while the machine is running at 600 rpm by assuming flux to be constantExplain the concept of power factor and its importance in electrical power systems.
- Draw and explain a typical power curve for a wind turbine and write the definition of the four important terms that are shown in the power curveA 20 kVA machine has a full load copper loss of 400 W, an iron loss of 150 W, and a mechanical loss of 200 W. Determine:a) Efficiency at 3/4 of full load with f.d.p. 0.8. Ans: 95,43%b) Performance at full load with f.d.p. 0.9. Ans: 96%c) Peak performance apparent power. Ans: 18,71 kVAd) Yield in the previous case for f.d.p. Unit. Ans: 96,39% I need the procedures to get these results. Thanksa) A sinewave is having a frequency of 50 Hz and instantaneous value of 250 Volts at 1.5 milli seconds. Find i) The maximum value of sinusoidal voltage waveform and ii) The value of voltage at 1.8 milli seconds. b) Determine the instantaneous equation for the voltage waveform shown in figure, if Vp%3D200 Volts, Time period is 20 milli seconds and =50 degrees. Vp Ф Upload your Answers steps in the "Final Answer Submission" Link provided in the Moodle. a) (i) Maximum value = a) (ii) Value of voltage at 1.8 ms = b) Angular frequency =