For a = 1.5m, determine the reactions at pin A and roller B. 1800 N/m A 4 m Solution: • There are two distributed loads acting on the beam, left and right. Replace them with equivalent concentrated loads respectively: 1. The distributed load on the left part of the beam is equivalent to F₁: o Magnitude of it: F₁ = N; o Location of it: x₁ = m to the right of A; 2. The distributed load on the right part of the beam is equivalent to F2: o Magnitude of it: F2 = N; o Location of it: X₂ = 600 N/m B 1. Reactions on A: 2 Reactions on R • The two supports are replaced by corresponding reactions: → m to the right of A;

Structural Analysis
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Chapter2: Loads On Structures
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There are two distributed loads acting on the beam, left and right. Replace them with equivalent concentrated loads
respectively:
1. The distributed load on the left part of the beam is equivalent to F₁:
Magnitude of it: F₁ =
N;
O
o Location of it: x₁ =
m to the right of A;
2. The distributed load on the right part of the beam is equivalent to F2:
o Magnitude of it: F₂ =
N;
o Location of it: x₂ =
. The two supports are replaced by corresponding reactions:
1. Reactions on A:
2. Reactions on B:
• Equilibrium equations:
1. EFx = 0: Ax =
2. EMA = 0: By =
3. EMB= 0: Ay=
=
;
N;
→
m to the right of A;
N;
Transcribed Image Text:There are two distributed loads acting on the beam, left and right. Replace them with equivalent concentrated loads respectively: 1. The distributed load on the left part of the beam is equivalent to F₁: Magnitude of it: F₁ = N; O o Location of it: x₁ = m to the right of A; 2. The distributed load on the right part of the beam is equivalent to F2: o Magnitude of it: F₂ = N; o Location of it: x₂ = . The two supports are replaced by corresponding reactions: 1. Reactions on A: 2. Reactions on B: • Equilibrium equations: 1. EFx = 0: Ax = 2. EMA = 0: By = 3. EMB= 0: Ay= = ; N; → m to the right of A; N;
For a = 1.5m, determine the reactions at pin A and roller B.
1800 N/m
A
4 m
Solution:
• There are two distributed loads acting on the beam, left and right. Replace them with equivalent concentrated loads
respectively:
1. The distributed load on the left part of the beam is equivalent to F₁:
o Magnitude of it: F₁ =
N;
o Location of it: x₁ =
m to the right of A;
2. The distributed load on the right part of the beam is equivalent to F2:
o Magnitude of it: F2 =
N;
o Location of it: X₂ =
600 N/m
B
1. Reactions on A:
2 Reactions on R
• The two supports are replaced by corresponding reactions:
→
m to the right of A;
Transcribed Image Text:For a = 1.5m, determine the reactions at pin A and roller B. 1800 N/m A 4 m Solution: • There are two distributed loads acting on the beam, left and right. Replace them with equivalent concentrated loads respectively: 1. The distributed load on the left part of the beam is equivalent to F₁: o Magnitude of it: F₁ = N; o Location of it: x₁ = m to the right of A; 2. The distributed load on the right part of the beam is equivalent to F2: o Magnitude of it: F2 = N; o Location of it: X₂ = 600 N/m B 1. Reactions on A: 2 Reactions on R • The two supports are replaced by corresponding reactions: → m to the right of A;
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