Following is the structural formula of the principal sex pheromone of the Douglas fir tussock moth (Orgyia pseudotsugata), a severe defoliant of the fir trees of western North America. (Z)-6-Heneicosene-11-one Several syntheses of this compound have been reported, one of which is shown: HO Br Br (Z)-6-Heneicosene-11-one alkyl bromide 1 hemiacetal 1 alkyl bromide 2 This synthesis involves the following steps: 1. Alkyl bromide 2 reacts with triphenylphosphine and butyllithium to form ylide 1; 2. Hemiacetal 1 is in equilibrium with aldehyde 2; 3. Aldehyde 2 reacts with ylide 1 to form oxaphosphetane 3; 4. Oxaphosphetane 3 expels triphenylphosphine oxide to form alkene 4 (the alkene is primarily formed in the desired Z configuration); 5. Alkene 4 is oxidized with PCC to form aldehyde 5; 6. Alkyl bromide 1 reacts with magnesium and ether to form Grignard reagent 6; 7. Grignard reagent 6 adds to aldehyde 5 to form tetrahedral intermediate 7; 8. Tetrahedral intermediate 7 reacts with dilute aqueous acid to form alcohol 8; 9. Alcohol 8 is oxidized with chromic acid to yield (Z)-6-Heneicosene-11-one. Diagram these steps on a separate sheet of paper, and then draw the structure of tetrahedral intermediate 7.

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter18: Functional Derivatives Of Carboxylic Acids
Section: Chapter Questions
Problem 18.38P: A step in a synthesis of PGE1 (prostaglandin E1, alprostadil) is the reaction of a trisubstituted...
icon
Related questions
icon
Concept explainers
Question
Following is the structural formula of the principal sex pheromone of the Douglas fir tussock moth (Orgyia pseudotsugata), a severe defoliant of the fir trees of
western North America.
(Z)-6-Heneicosene-11-one
Several syntheses of this compound have been reported, one of which is shown:
HO
Br
Br
(Z)-6-Heneicosene-11-one
alkyl bromide 1
hemiacetal 1
alkyl bromide 2
This synthesis involves the following steps:
1. Alkyl bromide 2 reacts with triphenylphosphine and butyllithium to form ylide 1;
2. Hemiacetal 1 is in equilibrium with aldehyde 2;
3. Aldehyde 2 reacts with ylide 1 to form oxaphosphetane 3;
4. Oxaphosphetane 3 expels triphenylphosphine oxide to form alkene 4 (the alkene is primarily formed in the desired Z configuration);
5. Alkene 4 is oxidized with PCC to form aldehyde 5;
6. Alkyl bromide 1 reacts with magnesium and ether to form Grignard reagent 6;
7. Grignard reagent 6 adds to aldehyde 5 to form tetrahedral intermediate 7;
8. Tetrahedral intermediate 7 reacts with dilute aqueous acid to form alcohol 8;
9. Alcohol 8 is oxidized with chromic acid to yield (Z)-6-Heneicosene-11-one.
Diagram these steps on a separate sheet of paper, and then draw the structure of tetrahedral intermediate 7.
• You do not have to consider stereochemistry.
• Draw the Grignard reagent as a covalent magnesium halide.
Previous
Next
Transcribed Image Text:Following is the structural formula of the principal sex pheromone of the Douglas fir tussock moth (Orgyia pseudotsugata), a severe defoliant of the fir trees of western North America. (Z)-6-Heneicosene-11-one Several syntheses of this compound have been reported, one of which is shown: HO Br Br (Z)-6-Heneicosene-11-one alkyl bromide 1 hemiacetal 1 alkyl bromide 2 This synthesis involves the following steps: 1. Alkyl bromide 2 reacts with triphenylphosphine and butyllithium to form ylide 1; 2. Hemiacetal 1 is in equilibrium with aldehyde 2; 3. Aldehyde 2 reacts with ylide 1 to form oxaphosphetane 3; 4. Oxaphosphetane 3 expels triphenylphosphine oxide to form alkene 4 (the alkene is primarily formed in the desired Z configuration); 5. Alkene 4 is oxidized with PCC to form aldehyde 5; 6. Alkyl bromide 1 reacts with magnesium and ether to form Grignard reagent 6; 7. Grignard reagent 6 adds to aldehyde 5 to form tetrahedral intermediate 7; 8. Tetrahedral intermediate 7 reacts with dilute aqueous acid to form alcohol 8; 9. Alcohol 8 is oxidized with chromic acid to yield (Z)-6-Heneicosene-11-one. Diagram these steps on a separate sheet of paper, and then draw the structure of tetrahedral intermediate 7. • You do not have to consider stereochemistry. • Draw the Grignard reagent as a covalent magnesium halide. Previous Next
Expert Solution
Step 1-Introduction

The Grignard reagent is furnished as R-MgX where R can be an alkyl or aryl group. The notable halides involved are chloride, bromide, and iodide. The bonding of R group to the metal center indicates that the carbon center has a high electron density and it can function as a base or nucleophile.

Notably, functional group interconversion is a key reaction associated with synthetic organic chemistry in which the added reagent transforms one functional group into another. For example, the oxidation of primary alcohol in the presence of PCC converts it into the aldehyde group. 

steps

Step by step

Solved in 2 steps with 4 images

Blurred answer
Knowledge Booster
Aromatic Compounds
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9781305580350
Author:
William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9781305080485
Author:
John E. McMurry
Publisher:
Cengage Learning