Find x such that the matrix is singular. ^-[34] A = -6 -4 X =
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![Find x such that the matrix is singular.
^-[34]
A
=
-6 -4
X =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd76112a2-3370-45d7-a044-1f0297120ded%2F75ab83c8-7532-45ea-b74a-0d25198824fd%2Fvlo9jwc_processed.jpeg&w=3840&q=75)
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- Calculate B(5,2) if B (a,r) = 2ar+r^37. ^- [6] -[73] Solve for X in the matrix equation: B-4X = A BUse the given definition to find f(A): If f(x) = a, + a,x + a,x + ... + an ^ is a polynomial function, then for a square matrix A, f(A) = aI + a,A + a,A?. + ... + 2 0 f(x) = 2 - 9x + x2, A = 4 9 -12 f(A) = 9. 2
- Determine the y^(invertible) of: a) y=(2x^2)/ (x-1) b) y= (3x^2) / (2x-1) c) y= (-4x^2)/(1-5x) (Include all steps )solve using matrix exponentials: For A=[(-1,0),(-2,1)] calculate I+tA+t^2/2 A^2 + t^3/6 A^3: [(_,0),(t(-t^2-6) / 3,_)] The actual value of e^(0.1A), to six decimal places, is [(0.904837, 0),(-0.200334, 1.105170)]. What do you get when you plug t = 0.1 into the approximation e^(tA)~~I+tA+t^2/2 A^2 + t^3/6 A^3? (Give six decimal places with no rounding.)Solve and find the values of x and y (5/(x-1))+(1/(y-2)) = 2 and (6/(x-1))-(3/(y-2)) = 1
