Find the transfer function,G(s)=Z1(s)/H(s) Find the state space model.
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Find the transfer function,G(s)=Z1(s)/H(s)
Find the state space model.
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- Alternatively, by moving the fixing point on the roll bar (where the link connects to the suspension system) closer or further away from the roll bar will also increase or decrease torsional stiffness. Stiffer Softer Q.2 Is this roll bar set to full 'stiff' or full 'soft'?Damped System What type of damping do you want for your car suspension? (A) Under damped (B) Critically damped (C) Over damped (D) Suspension systems are uselessQ5/ In vehicle suspension design it is desirable to minimize the mass of all components. You have been asked to select a material and dimensions for a light spring to replace the steel leaf-spring of an existing truck suspension. The existing leaf-spring is a beam, shown schematically in the figure. The new spring must have the same length L and stiffness S as the existing one, and must deflect through a maximum safe displacement 8max without failure. The width b and thickness t are free variables. L Load F 6= 1 FL³ 48 EI 10₂L² 6 #E 1=bt³/12 8max = Derive a material index for the selection of a material for this application. Note that this is a problem with two free variables: b and t; and there are two constraints, one on safe deflection 8max and the other on stiffness S. Use the two constraints to fix free variables.
- TRUE OR FALSE1. The primary and secondary suspensions are designed to achieve very poor ride quality, not safe performance during curve negotiation and bad dynamic behavior on a tangent track. 2. Each bogie frame is connected to car body through side bearings. 3. the wheel sets are located within a frame, either a bogie or directly in the vehicle, and are restrained by a large yaw stiffness. 4. When considering maintenance for railways, often the consequences can easily be changed. 5. Maintenance can only have positive effects. 6. Corrective maintenance also called as down systems. 7. the disadvantage of this system is the relatively low frequency of maintenance.O geas use im steering aio plane Spuy bevel Helical Coerm usd after motor to damyping vtalarim Spur gear O Charn © Neme Belt follwer las mere frician with Cam flat Roiler O Icmife (O None follower lised to toensminsiag wsn Dewer named flat®AMa the anble © kmit @ Roller ylaping Example on All a the above BscotchY arc ☺ Cranic @ duick retunnam Ro forcwer esed Ao Aoenymision low power named Roller (O flat kmife Au athe 9- abve(Repost) Dynamic force analysis for linkage mechanism needs to be solved aswell
- Why is a torsion bar suspension considered as a two-inertia system? Please include references.480 ft-lbf First Gear (2.66) Final Drive (3.42) Axle Torque Thrust Force Figure 2 - Corvette Z06 and its transmission schematic. You start by measuring the 60-0 mph braking performance, which is accomplished along 30.56 m. The test weight (including the driver) was found to be 1510.5 kgf. 1) "Fuel is spent to make the vehicle go uphill, as you are aware. However, the fuel will not be restored if the vehicle is brought back from the hilltop to the initial elevation level."ANALYSE this statement under the laws of Thermodynamics.Cylinder uses hydraulic oil ISO 68, is Shown in d= 2cm HE Figure Fem Find © Pressure required to lift 1300kg from rod end side ? 23 Piston's velocity in the cylinder it t takes 17 sec to move from bottom tokp in the Cyind or? CS Scanned with CamScanner
- Question 1: A race car is turning (cornering) on a flat road, as shown in Figure Q1-1. The speed of the car is 300 kph and the turning radius is 260 m. Having the car parameters as below, answer questions a) and b). ● . ● ● m = 890 (kg) (57% of the weight is on the rear axle); Air density = 1.225 (kg/m3); Equivalent aerodynamic lift coefficient for front axle= -0.915 (-); Aerodynamic frontal area= 1.11 (m²); Slip angle of the front tyres= +2.4 (°); Slip angle of rear tyres= +1.2 (°); The steering angle of wheels= -1.9 (°); The efficiency of the drivetrain from the engine to the contact patch of tyres is 100%. 8=-1.9°- ---R=260 m α = +2.4° αR = +1.2° Figure Q1-1 Motion of the vehicle and the angles a) Calculate the engine power delivered to tyres to overcome the total induced drag due to lateral force.Torsion bar based suspension system of a car is given below. The spring motion is provided by a torsion bar fastened to the arm on which the wheel is mounted. The torsion bar is made of AISI 4140 carbon steel. The force on the wheel is in average 3 kN, however, due to the road conditions this force may oscillate between 2-4 kN. Assuming the arm of the wheel is strong enough, we want to design the diameter of the torsion bar, considering %99 reliability and infinite life. What would be the diameter of the torsion bar? 2500N Arm 300mm Torsion bar- Bearing- 300mm 100mmProblem 4. For the belt drive shown below calculate the contact angle 0, if: D %3D 100 mт; d 3 30 тm; C = 300 mm. D-d 20 sin V4c² - (D – d)²- -1 D-d sin 20 Op