Find the length of the tangent drawn from the point (4, 6) to the circle 3х^2 + 3у^2 + 12х +4у -35=0.

What are the coordinates of the points in the graph of y-x+ 6x- 13=0 in which the tangent line is horizontal? A (2.-V5).(2, V5) B (4, - 5),(4,5) © (1.-2/2).(1.2/7) (3,-2),(3,2)

Find the distance between the points (-1,2) and (1,-1)

Find the distance between the point (-2,3) and (1,7)

Find the distance between the points (0,5) and (-3,2) Distance =

Find the slope the tangent to the curve y² = 3x² + 4 through point (-2, -4)

The distance between the points (-2,2,0) and (1, -1,0) is 3/2. True False

Write the equation of the line that is tanget to the circle (x-1)^(2)+(y-2)^(2)=25  at the point (4,6).