Find the AH for the reaction below, given the following reactions and subsequent AH values: B₂H6(g) + 6 Cl2(g) → 2 BC13(g) + 6 HCl(g) AH = -72.5 kJ BC13(g) + 3 H₂O(1)→ H3BO3(g) + 3 HCI(g) B2H6(g) + 6H₂O(l) → 2 H3BO3(s) + 6 H₂(g) ΔΗ = + 60.8 kJ 1/2 H₂(g) + 1/2 Cl2(g) → HCI(g) - 150.3 kJ ΔΗ = -

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter12: The Solid State
Section12.3: Bonding In Ionic Compounds: Lattice Energy
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Find the AH for the reaction below, given the following reactions and subsequent AH values:
B2H6(g) + 6 Cl2(g) → 2 BCI3(g) + 6 HCI(g)
ΔΗ = – 72.5 kJ
BC13(g) + 3 H₂O(l) → H3BO3(g) + 3 HCI(g)
B2H6(g) + 6 H₂O(l) → 2 H3BO3(s) + 6 H2(g)
ΔΗ = + 60.8 kJ
1/2 H₂(g) + 1/2 Cl₂(g) → HCI(g)
150.3 kJ
ΔΗ = -
Transcribed Image Text:Find the AH for the reaction below, given the following reactions and subsequent AH values: B2H6(g) + 6 Cl2(g) → 2 BCI3(g) + 6 HCI(g) ΔΗ = – 72.5 kJ BC13(g) + 3 H₂O(l) → H3BO3(g) + 3 HCI(g) B2H6(g) + 6 H₂O(l) → 2 H3BO3(s) + 6 H2(g) ΔΗ = + 60.8 kJ 1/2 H₂(g) + 1/2 Cl₂(g) → HCI(g) 150.3 kJ ΔΗ = -
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