F12–28. The car is traveling along the road with a speedof v = (2 s) m/s, where s is in meters. Determine themagnitude of its acceleration when s = 10 m.v = (2s) m/s50 m n

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Answered: F12–28. The car is traveling along the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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F12–14. The dragster starts from rest and has a velocity described by the graph. Construct the s-t graph during the time interval 0 sis 15 s. Also, determine the total distance traveled during this time interval. v (m/s) v = 30 t 150 -v = -151 + 225 (s) 15
The acceleration of a crate sliding down a ramp is given by ax = (0.25t²) m/s² and ay = (1.51³) m/s², where t is in seconds. When t = 0s, Vx= 3 m/s and Vy= 4 m/s. Determine the magnitude of the crate's velocity when t = 2 s.
A body moves along a linear path and its rate of change of velocity varies with time and is written as a=2-3t, where t is the time in second. After 5 second, from start of observation its velocity is determined to be 20 m/s. After 10 second from start of observation, the body is at 85 m far from the origin. Determine the following:a. Rate of change of velocity and velocity at the start of motion.b. Distance from the origin at the start of observationc. Time after start of observation in which the velocity becomes zero.
The car is traveling at a speed of 95 km/h as it approaches point A. Beginning at A,the car decelerates at a constant rate of 2 m/s2 until it gets to point B, after which itsconstant rate of decrease of speed is 0.9 m/s2as it rounds the interchange ramp.Determine the magnitude of the total car acceleration:a) just before it gets to B,b) just after it passes B, andc) at point C.
If a car accelerates at the rate of a in t seconds and decelerated at the rate of 0.5a for 2t seconds pefore it stops, determine the distance it has travelled if it started from rest. Ans: 3/2 at^3
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The driver of a car, which is initially at rest at the top A of the grade, releases the brakes and coasts down the grade with an acceleration in feet per second squared given by a = 3.23 -0.006v², where v is the velocity in feet per second. Determine the velocity VB at the bottom B of the grade. A Answer: VB = i 605' ft/sec. B
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F12–28. The car is traveling along the road with a speed of v = (2 s) m/s, where s is in meters. Determine the magnitude of its acceleration when s = 10 m. v = (2s) m/s 50 m n