F1 hybrid is obtained from the following cross: Parent 1: AB/AB; d/d; E/E Parent 2: ab/ab; D/D; e/e Assume that all genes are sorted independently except for genes A and B, which are tightly linked and show zero recombination. Following a testcross of F1, what proportion of the F2 progeny will be phenotypically like parent 1? O 1/32 O 1/8 O 1/16 O 1/4 9/64

F1 hybrid is obtained from the following cross: Parent 1: AB/AB; d/d; E/E Parent 2: ab/ab; D/D; e/e Assume that all genes are sorted independently except for genes A and B, which are tightly linked and show zero recombination. Following a testcross of F1, what proportion of the F2 progeny will be phenotypically like parent 1? O 1/32 O 1/8 O 1/16 O 1/4 9/64

Name: F1 hybrid is obtained from the following cross:Parent 1: AB/AB; d/d;
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: F1 hybrid is obtained from the following cross:Parent 1: AB/AB; d/d; E/EParent 2: ab/ab; D/D; e/eAssume that all genes are sorted independently except for genes A and B, which aretightly linked and show zero recombination. Following a testcross of F

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

See similar textbooks

Similar questions

F1 hybrid is obtained from the following cross: Parent 1: AB/AB; d/d; E/E Parent 2: ab/ab; D/D; e/e Assume that all genes are sorted independently except for genes A and B, which are tightly linked and show zero recombination. Following a testcross of F1, what proportion of the F2 progeny will be phenotypically like parent 1? O 1/8 O 1/4 O9/64 O 1/16
A three-point cross was conducted, 8500 progeny were evaluated, and the genetic map was determined to be:Gene J----3mu----Gene K-----5mu-----Gene LA total of 8 double cross-over progeny were identified among the 8,500 evaluated. What is the coefficient of coincidence?
In a fungus with four ascospores, a mutant allele lys-5causes the ascospores bearing that allele to be white,whereas the wild-type allele lys-5+ results in black ascospores. (Ascospores are the spores that constitute thefour products of meiosis.) Draw an ascus from each ofthe following crosses:a. lys-5 × lys-5+b. lys-5 × lys-5c. lys-5+ × lys-5+
We have dealt mainly with only two genes, but the sameprinciples hold for more than two genes. Consider thefollowing cross:A/a ; B/b ; C/c ; D/d ; E/e × a/a ; B/b ; c/c ; D/d ; e/ea. What proportion of progeny will phenotypicallyresemble (1) the first parent, (2) the second parent,(3) either parent, and (4) neither parent?b. What proportion of progeny will be genotypically thesame as (1) the first parent, (2) the second parent,(3) either parent, and (4) neither parent?Assume independent assortment.
Mice of the genotypes A/A ; B/B ; C/C ; D/D ; S/S anda/a ; b/b ; c/c ; d/d ; s/s are crossed. The progeny are intercrossed. What phenotypes will be produced in the F2 andin what proportions? [The allele symbols stand for thefollowing: A = agouti, a = solid (nonagouti); B = blackpigment, b = brown; C = pigmented, c = albino; D =nondilution, d = dilution (milky color); S = unspotted,s = pigmented spots on white background.]
In this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…
An individual heterozygous for four genes, A/a • B/b •C/c • D/d, is testcrossed with a/a • b/b • c/c • d/d, and 1000progeny are classified by the gametic contribution ofthe heterozygous parent as follows:a • B • C • D 42A • b • c • d 43A • B • C • d 140a • b • c • D 145a • B • c • D 6A • b • C • d 9A • B • c • d 305a • b • C • D 310a. Which genes are linked?b. If two pure-breeding lines had been crossed toproduce the heterozygous individual, what would theirgenotypes have been?c. Draw a linkage map of the linked genes, showing theorder and the distances in map units.d. Calculate an interference value, if appropriate
A pureline plant of genotype A/A ; b/b is crossed to another pureline plant a/a ; B/B. The F1 progeny is then selfed. The progeny from the selfing of the F, that are not purlines will be about O 1/4 O 9/16 O 3/4 O 1/3 O 1/2
In'a Mendelian monohybrid cross, the F2 generation consists of 1/4 red-flowered, 1/2 pink-flowered, 1/4 white-flowered individuals. What does this indicate? For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). 14px A Ix BIUS Paragraph Arial ABC 田三 x² X2 田用因 Ť {} +]
An individual heterozygous for d e f (D/d E/e F/f) was crossed to a homozygous recessive individual (d/d e/e f/f). The following offspring were recovered.d e + 39+ e f 372d + f 7+ + f 47+ e + 5d + + 412What is the correct order of these genes? EDF DFE DEF
In corn, the genes for tassel length (alleles T and t) andrust resistance (alleles R and r) are known to be on separate chromosomes. In the course of making routinecrosses, a breeder noticed that one T/t ; R/r plant gaveunusual results in a testcross with the double-recessivepollen parent t/t ; r/r. The results wereProgeny: T/t ; R/r 98t/ t ; r/r 104T/t ; r/r 3t/t ; R/r 5Corncobs: Only about half as many seeds as usuala. What key features of the data are different from theexpected results?b. State a concise hypothesis that explains the results.c. Show genotypes of parents and progeny.d. Draw a diagram showing the arrangement of alleleson the chromosomes.e. Explain the origin of the two classes of progenyhaving three and five members.
But for part A if you cross dd ll x DD LL, won't all the offspring be DdLl (dark colored and long legged), so wouldn't NONE of the offpspring have short legs and light body coloration? Isn't the 9:3:3:1 ratio only for two heterozygous dihybrid crosses? Where is the 25/4 coming from? Could you draw a punnett square to demonstrate.