Expressions 0112 6760 ELE 1323 a. Convert the following infix expression to post-fix (reverse-polish) notation: (9-2-1)*(4+5) b. Draw the expression tree for the following infix expression: ((5-2)*4)/(3+1) Sp c. Evaluate the following post-fix expression using a stack. Show all intermediate steps of the computation, that is, sha what is stored in the stack after each symbol in the string is processed: 3 2+4*62-/
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- Convert the following Infix Expression to a Postfix Expression using stack. A + B / C - (P * Q) + REvaluate the following postfix expression using stack. 823+ - 382/+* 2+6 A BI -3. Suppose + and - have HIGHER PRECEDENCE than * and /, and that you have the following infix expression: 3* 5+2-(6+3/3) Convert the expression from infix to postfix. Fill out the table, showing each step you take. List the action of each step and show the contents of the stack and postfix expression after completing the action. The first step is done for you. Popping an element off the stack and appending it to the postfix expression is one step. Action Add 3 to postfix. Stack (empty) Evaluate the postfix expression to produce the final integer result. Postfix 3
- The objective of this assignment is to write an algorithm that convert a postfix expression into infix using a Stuck ADT. Display how the algorithm performs by showing the state of the stack while converting the following expression: ab/c*de*-4. Sort elements in an array-based stack in ascending order, i.e. make the smallest element to be the top element of the stack. E.g. given the stack elements (from bottom to top): 90, 70, 80, 10, sort the elements to make the stack elements become (from bottom to top): 90, 80, 70, 10. The only data structure you can use is array-based stack. In addition to the given stack, you can use only one extra stack to store some temporary data. Given a stack st, use one extra stack, tmpst, to store temporary data. Here are some hints of the idea. Pop out the top element of st to a variable tmp. If the stack tmpst is empty, push tmp onto tmpst; if tmpst is not empty, pop out its top element and push that element onto st until the top element of tmpst is smaller than tmp, then push tmp onto tmpst .. a. Write a program to implement the stack based sorting. b. Take the input (90, 70, 80, 10) as an example. c. Print all the push and pop operations in proper format. d. At the end, print the sorted…Find out how the stack functions when allowed to be itself.
- Using push and pop operations, show how the following Postfix expression would be calculated using a stack. Use the pictorial method shown on slide 48 of Chapter 18 lecture as a guide. Indicate push and pop operations. You do not need to draw boxes. 10 6 * 10 + 2 / 5 + = What is the calculated VALUE of the expression?A drop-out stack is a data structure that acts just like a stack except that if the stack size is n, and the n + 1 element is pushed, the first element is lost. Using an array, create a drop-out stack. (Hint: A circular array implementation would be appropriate.)Find out how well the stack functions when it is allowed to be itself.
- Select the statements that apply to the use of the frame pointer. EBP is often called the base pointer or frame pointer because it holds the base address of the stack frame. EBP does not changes value during the procedure. EBP need not be restored to its original value when a procedure returns. A procedure can explicitly access stack parameters using constant offsets from EBP.Using a stack, implement a function is_valid_expr(expr: str), the function takes in a string representing a mathematical expression, which may include parenthesis, the function returns true if expr is valid, otherwise, it returns false. A valid expression is one that has a matching closing parenthesis for every opening one. Here are some examples: 1 + 10 à valid (1+2) à valid (2 * 3) + (4 * 2 + (x – 1)) à valid (1 + 1) + (2 * x)) à invalid ((1 + 5) * x à invalidinput: 23+7* 26+9/ 14 2 + 160/ 99 2 + 50/24 - 100 4/3 * 20 + 143 *19 + 12/3+7* 23 7 + 10 * 14 + 19 - 22 * 16/ output: expression 23 +7* evaluates to 35 expression 2 6 + 9 / evaluates to 0 expression 14 2 + 160/ evaluates to 0 expression 99 2 + 50 / 24 - evaluates to -22 expression 100 4/3 * 20+ evaluates to 95 expression 14 3 * 19 + 12/3 + 7* evaluates to 56 expression 23 7 + 10 * 14 + 19 - 22 * 16/ evaluates to 405