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A: The solution is given below -
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Q: Why the relative reactivity of SN2 is tertiary<secondary<primary<allyl, phenyl ? (explanation)
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Explain Radical Halogenation at an Allylic Carbon ?
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- Rank the following radicals in order of increasing stability.Why does Hammett Equation only apply to meta and para substituted rings and not others? ExplainAs we will learn, many antioxidants–compounds that prevent unwanted radical oxidation reactions from occurring–are phenols, compounds that contain an OH group bonded directly to a benzene ring.a.) Explain why homolysis of the O–H bond in phenol requiresconsiderably less energy than homolysis of the O–H bond in ethanol(362 kJ/mol vs. 438 kJ/mol).b.) Why is the C–O bond in phenol shorter than the C–O bond in ethanol?
- 3.) Butanedionic Why completely soluble in water? Why insoluble in HCl? Why completely soluble in NaOH? Why completely soluble in NaHCO?Can you explain how an alkene bonds to a metal like in this compound using some orbital diagrams?Zaitsev's rules predicts generally formed preferentially by both E1 and E2 mechanisms. A) more substituted alkenes B) less substituted alkenes C) tertiary alkyl halides D) primary alkyl halides are
- 1) Which of the following molecules would be expected to have the HIGHEST heat of hydrogenation? a. b. C. d. e.For SN2 Explain the order in which 1o (primary) alkyl halides reacted and explain why. The 1o primary alkyl halides are: (see picture below) 1-chlorobutane 1-bromobutane 1-chloro-2butene benzylchlorideUse the Hammond postulate to explain why (CH3)2C = CH2 reacts faster than CH3CH = CH2 in electrophilic addition of HX.
- Select the keyword or phrase that will best complete each sentence. Key terms: backside carbocation elimination frontside hyperconjugation inversion maintenance nucleophile product racemization stronger substitution weaker Alkyl halides undergo A orbital. reactions with Brønsted-Lowry bases. is a sp² hybridized and trigonal planar and contains a vacant p All SN2 reactions proceed with in attack of the nucleophile, resulting of configuration at a stereognic center. Spreading out charge by the overlap of an empty p orbital with an adjacent o bond is called Equilibrium favors the products of nucleophilic substitution when the leaving group is a base than the nucleophile. According the to Hammond postulate, the stability of the determines the rate of its formation. The formation of equal amounts of two enantiomeric products from a single starting material is called A is an electron-rich compound, which donates a pair of electrons to an electron deficient compound, forming a covalent bond.…Rank the alkenes stability from most to least and explain whyHow To Assign the Prefixes E and Z to an Alkene ? discuss by steps ?