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- A test of the claim that the proportion of students taking more than 9 units is more than 42% produces the test statistic z = 1.76. Find the P-value.Find the z score of the value 2.5 in the data set {1.90, 3.00, 2.5, 3.71, 2.12, 1.76, 2.71,1.39, 4.00, 3.33} with s = 0.8539 and x =2.642 (Don't Hand writing in solution) .Determine the two values of z such that the middle 58% of the data lie between the two z-values. Oz=-0.81 and = 0.81 Oz=-0.55 and = = 0.55 Oz= -0.88 and z = 0.88 Oz=-0.77 and z = 0.77 > Next Question
- At α = 0.01, check whether the shoe number differs between male and female students. In the attachment, you send only PART of the data, what the data looks like.Using the z-table, determine the z-score that has 15% of the area to the right of itExercise 1: Use the z-table to find the area that corresponds to each of the following z-score: 6. z = 3 7. z = -3 8. z = -2.3 9. z = -1.9 10. z = 1.96 1. z = 0.36 2. z = 1.68 3. z = -1.8 4. z= -2.5 5. z = 2.77
- find the value represented by z-score of 2.043, given u=63 and o=4.25A random sample of 144 residents in a community produced 88 residents testing positive for the herpes simplex virus (which causes cold sores). Researchers wish to test whether proportion testing positive is different from .50. Use α=.05.Life on Other Planets Forty-six percent of people believe that there is life on other planets in the universe. A scientist does not agree with this finding. He surveyed 100 randomly selected individuals and found 40 believed that there is life on other planets. At =α0.01, is there sufficient evidence to conclude that the percentage differs from 46%? Use the P-value method with tables. Do not round intermediate steps. H0= (claim or not claim) H1= (claim or not claim) This hypothesis test is a (one tailed or two tailed) test Critical value(s)= z= (Reject or do not reject) the null hypothesis is there enough evidence to support the claim?