Example: The half-wave rectifier in the figure has a 120-V rms source at 60 HzR = 500 02, and C= 100 µF. Determine (a) an expression for output voltage, (b) the peak-to-peak voltage variation on the output, (c) an expression for capacitor current, (d) the peak diode current, and (e) the value of C such that AVo is 1 percent of Vm

Example: The half-wave rectifier in the figure has a 120-V rms source at 60 HzR = 500 02, and C= 100 µF. Determine (a) an expression for output voltage, (b) the peak-to-peak voltage variation on the output, (c) an expression for capacitor current, (d) the peak diode current, and (e) the value of C such that AVo is 1 percent of Vm

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter59: Motor Startup And Troubleshooting Basics

Section: Chapter Questions

Problem 12SQ: How is a solid-state diode tested? Explain.

See similar textbooks

Similar questions

What is the difference between a diode and rectifier?
How is a solid-state diode tested? Explain.
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20V
A single phase – half wave controlled rectifier with freewheeling diode is supplying a load consistingseries connected a resistor and an inductance from a 70.7V (RMS), 50Hz sinusoidal AC source.The firing delay of the thyristor is 90° and the load values are R=10Ω, L=0.1 H. Define the loadcurrent expression and draw the load current by calculating for first two periods. And calculate theaverage values of the load voltage and current.
Draw the input waveform and output waveform for the circuit given below with proper values marked in the figure. Assume D1 as germanium and D2 as silicon diodes. Input Vpp%3D20V, V1=3 V and V2=10 V. R D2 D1 Vin Vout V1 V2 Maximum voltage of output waveform Minimum voltage of output waveform Ps
In a full wave rectifier circuit involving double diodes, a sinusoidal input signal of the following nature is applied e=10 sin(500*pi*t) V. What will be value of the dc voltage obtained at the output of the rectifier.
Considering a clamper circuit, where capacitance C, load R, the cut-in voltage of diode are unknown, which is the correct statement 1- the dc level of the signal changes 2- the peak-to-peak value of signal changes 3- the shape of signal changes 4- the dc level shifts up 5- the dc level shifts down
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the above
Select any diode from LTSpice Library. (The type of diode should either be RECTIFIER or SILICON) Create a Half-Wave Rectifier circuit. Use a resistor of 1000 Ohms. Input Voltage should be 95VAC - 65Hz Plot both the Input voltage and output voltage. Determine the Voltage drop across the diode by subtracting the output voltage to the input voltage peaks. Create a Bridge-Type Full Wave Rectifier Circuit. Repeat the steps done on the Half-Wave Rectifier circuit.
Draw the input waveform and output waveform for the circuit given below with proper values marked in the figure. Assume D1 as silicon and D2 as germanium diodes. Input Vpp=20V. V1=5 V and V2=9 V. R www D1 Vin Vout v1 V2 Maximum voltage of output waveform Minimum voltage of output waveform
Q1/ a/Draw the output voltage waveform for the bridge rectifier in this figure : D D4 120 V ms D D2 R3 Vout B/ What PIV rating is required for the diodes in a bridge rectifier that produces an average output voltage of 50 V? Q2/ Determine the minimum input voltage required for regulation to be established in the figure. Assume an ideal zener diode with IzK = 1.5 mA and Vz= 14 V. R 560 N VIN
5-For single phase half-wave controlled rectifier with a freewheeling diode connected across the inductive load, the supply voltage is 220V (RMS). The mean value of the output voltage for a=45 is: 100.7V 70.9V 84.5V 6-For fully controlled single phase bridge rectifier with inductive load (R=102, L=50mH), F=50HZ and a=45', the load current is: Continuous discontinuous verge continuous 7-Fully controlled three phase bridge rectifier circuit is supplied through delta-star transformer. For highly inductive load, the waveform of the line supply current (primary line current of the transformer) is: Square quasi-square six- step