Example problem: 1. A timber beam 10 cm wide by 30 cm high and 4.0 m long carries the loading as shown below. If the maximum flexure stress is 828 kPa. for what maximum value of uniformly distributed wo will the shear under P be zero and what is the value of P. *10 cmy ||||w| = kk/m ! ↓ 30 cm C 3.0 m 4.0 m RA 1.0 M Re

Example problem: 1. A timber beam 10 cm wide by 30 cm high and 4.0 m long carries the loading as shown below. If the maximum flexure stress is 828 kPa. for what maximum value of uniformly distributed wo will the shear under P be zero and what is the value of P. *10 cmy ||||w| = kk/m ! ↓ 30 cm C 3.0 m 4.0 m RA 1.0 M Re

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A timber beam 150 mm wide by 250 mm deep is to be reinforced at bottom by steel plate 10 mm thick. w (kN/m) = ? 150 mm wood 250 mm 3.5 m steel 10 mm 50 mm a. What is the value of the transformed moment of Inertia? P. What should be the maximum w in (kN/m) that the beam should carry if it has a uniform distributed load across its 3.5 m span? Allowable stress of wood is 6.9 MPa and allowable stress of steel is 100 MPa. n=15.
P 3) A simply supported beam constructed by four woods nailed together as shown in the figure. If each nail can support a shcar force of V-11 kN, and the allowable shcar stress for the material is (twood)Jallow=2 MPa, Considering the only shear effect; A 3m В 3m + a) Calculate the P force that the beam can carry safely. b) Using the calculated value of Pin (a), determine the maximum distance between the nails. 12em 12 Figure-3
20 A 2500 KN 2.m B G 2m C F 2m D Elde ANALYZE FORCES TO FOR TENSION OR COMPRESSION PLEASE SHOW ALL LOGIC
6.58 A timber beam is 100 mm wide and 150 mm deep. The beam is simply supported and carries a central concentrated load W. If the maximum stress in shear is 2 N/mm², what would be the corresponding load Won the beam ?
A beam has a uniform dead load and live load has a fixed support at both ends. If the beam properties are given below, what is the stress at bottom of the beam section at the midspan. (MPa) Properties: Beam width = 263 mmBeam height = 466 mmWLL = 12.52 kN/mWDL = 18.03 kN/mSpan of the beam = 11 mPrestressing force = 323 kNeccentricity = 105 mm
A pre stressed concrete simple beam having a cross section of300mmx600mm is subjected to a pre stressing force in steel whicheventually reduce to 1200KN due to losses acting on a parabolic tendons.The beam carries a total uniform distributed load of 20 KN/m includingbeam’s weight. Using three methods calculate the total stresses at midspan section of the beam. Given:B = 300mmD = 600mmP = 1200KNW = 20 KN/mE @ mid span = 50 mmE @ end section = 0 mmL = 10 mm Det. the total stresses of the extreme bottom fiber at midspan using load balancing method. (Mpa)
A 5-m long simply supported timber beam carries two concentrated loads, as shown in Figure. Determine the maximum horizontal shear stress that occurs in * ,the beam at any location within the span length. Use l = 1139 x 106 mm4 150 mm 14.0 kN 42.0 kN 450 mm 2m 2m 1m 100 mm 16.80 KN 39.20 ΚN 150 mm 159.2 kPa O 871 kPa O 456 КPa О 398 kPa 1
1000 N/m Given: A cantilever beam has loading and cross section as shown. The allowable stress is 64 MPa. 150 mm Determine: the minimum width for the beam 6 m b
Pls help me I need answer for this asap. Thank you!! The frame is used to support the wood deck in a residential building. Calculate and illustrate the magnitude loading in kN/m acting at beam DE. Set a = 1.5 and b =4. Dead Load = 0.54 kN/m2Live Load = 1.92 kN/m2
Activity: 1. A single span timber beam having an unsupported length of 8m has a cross section of 200mm x 350mm. It carries a uniformly distributed load "W" kN in throughtout its span. Allowable bending stress Fb = 9.6 MPa and E = 13800MPA. a. What is the allowable bending stress with size factor adjustment b. What is the allowable bending stress with slenderness factor adjustment. What is the uniform load of w in N that beam could carry. m
A simply supported wood beam AB with span length L = 4 m carries a trapezoidal distributed load (see Figure 1). Calculate the maximum bending stress due to the load if the beam has a rectangular cross section with width b = 140 mm and height h = 240 mm. 5.8 kN/m 2.9 kN/m A B Figure 1 4 m
A floor slab 100 mm thick is cast monolithically with beams 250 mm wide 450 mm deep spaced 1.2 m on centers, on simple supports over a span of 5.0 m. The floor supports a superimposed service dead load of 1.0 kPa and service live load of 2.1 kPa. Usingf.-21 MPa, long bar f, = 415 MPa, calculate the following: 1. Factored uniform load on a typical interior beam in kN/m using load factors of 12 for dead load and 1.6 for live load. B. 11.448 Effective flange width of a typical interior beam in mm. B. 1,850 A 8.928 C 11.028 D. 9.960 2. A 1,500 Required amount of 16-mm-flexure bars for a typical interior beam in positive bending Use 10-mm-dia. stirrups C. 1,200 D. 1,466 3. B. 246 mm C.331 mm D. 427 mm A 512 mm ?