Example 8.20(b). A four-pole, lap-wound shunt generator has 300 armature-conductors and a flux/pole of 0.1 Wb. It runs at 1000 r.p.m The armature and field-resistances are 0.2 ohm and 125 ohms respectively. Calculate the terminal voltage when it is loaded to take a load current of 90 A Ignore armature reaction. (Nagpur University, April 1999)

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Chapter33: Single-phase Motors
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I need answer within 20 minutes please please with my best wishes
Load current = 227/10 = 22.7 A, Power absorbed by the load is = 227 x 22.7 = 5,153 W
Example 8.20(b). A four-pole, lap-wound shunt generator has 300 armature-conductors and
a flux/pole of 0.1 Wb. It runs at 1000 r.p.m. The armature and field-resistances are 0.2 ohm and 125
ohms respectively. Calculate the terminal voltage when it is loaded to take a load current of 90 A.
Ignore armature reaction.
Solution. First, the e.m.f .should be calculated
(Nagpur University, April 1999)
Transcribed Image Text:Load current = 227/10 = 22.7 A, Power absorbed by the load is = 227 x 22.7 = 5,153 W Example 8.20(b). A four-pole, lap-wound shunt generator has 300 armature-conductors and a flux/pole of 0.1 Wb. It runs at 1000 r.p.m. The armature and field-resistances are 0.2 ohm and 125 ohms respectively. Calculate the terminal voltage when it is loaded to take a load current of 90 A. Ignore armature reaction. Solution. First, the e.m.f .should be calculated (Nagpur University, April 1999)
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