Evaluate the integral by interpreting it in terms of areas. L² (3x-14) de Part 1 of 3 We are concerned with the segment of the line y=x-14 that begins at (0, -14) and that ends at (7, 21/2✔ Part 2 of 3 Part 3 of 3 y Therefore, 10 5 -51 -10 -15 2 2-14 dx s 4 x-140 <- 14 dx can be interpreted as the area of the triangle above the x-axis minus the area of the triangle below the x-axis. The area of the lower triangle is bh = 28✔ 175 4 6 X X 21/2). 28 and the area of the upper triangle is 63
Evaluate the integral by interpreting it in terms of areas. L² (3x-14) de Part 1 of 3 We are concerned with the segment of the line y=x-14 that begins at (0, -14) and that ends at (7, 21/2✔ Part 2 of 3 Part 3 of 3 y Therefore, 10 5 -51 -10 -15 2 2-14 dx s 4 x-140 <- 14 dx can be interpreted as the area of the triangle above the x-axis minus the area of the triangle below the x-axis. The area of the lower triangle is bh = 28✔ 175 4 6 X X 21/2). 28 and the area of the upper triangle is 63
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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