E(t) 240, 0sts 50 t> 50 is applied to an LR-series circuit in which the inductance is 30 henries and the resistance is 3 ohms. Find the current i(t) if i(0) = 0. Osts 50 t> 50

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16.
MY NOTES
17.
18
An electromotive force
i(t)=
240, 0sts 50
E(t) =
t> 50
is applied to an LR-series circuit in which the inductance is 30 henries and the resistance is 3 ohms. Find the current i(t) if i(0) = 0.
Osts 50
MY NOTES
Need Help? Read It
L(t) =
i(t) =
Graph i(t)
Ar LR-series circuit has a variable inductor with the inductance defined by
{
50
40
i (t)
30
12 20.
Find the current i(t) if the resistance is 0.1 ohm, the impressed voltage is E(t) = 5, and i(0) = 0.
Ost<20
20
ASK YOUR TEACHER
10
O
n
10
20
40
i(t)
50
30
20
ASK YOUR TEACHER
10
1
-2/04
dv
dit
t> 50
Watch It
Ost <20
O
Need Help? Read It
t≥ 20
= mg -kv,
10
PRACTICE ANOTHER
PRACTICE ANOTHER
20
30
30
40
40
t
t
Viewing Saved Work Revert to Last Response
O
where k >0 is a constant of proportionality. The positive direction is downward
(a) Solve the equation subject to the initial condition v(0) = 0
v(t) =
i (t)
50
40
30
20
10
i (t)
50
40
30
20
10
5
5
10
(0) Use the solution in part (a) to determine the limiting, or terminal, velocity of the mass.
10
15
15
MY NOTES
20 25
20
25
In (14) of Section 1.3 we saw that a differential equation describing the velocity v of a falling mass subject to air resistance proportional to the
instantaneous velocity is
30
30
ASK YOUR TEACHER
t
(c) If the distance s, measured from the point where the mass was released above ground, is related to velocity v by ds/dt = v(t), find an
explicit expression for s(t) if s(0) = 0.
ОО
s(t) =
Transcribed Image Text:16. MY NOTES 17. 18 An electromotive force i(t)= 240, 0sts 50 E(t) = t> 50 is applied to an LR-series circuit in which the inductance is 30 henries and the resistance is 3 ohms. Find the current i(t) if i(0) = 0. Osts 50 MY NOTES Need Help? Read It L(t) = i(t) = Graph i(t) Ar LR-series circuit has a variable inductor with the inductance defined by { 50 40 i (t) 30 12 20. Find the current i(t) if the resistance is 0.1 ohm, the impressed voltage is E(t) = 5, and i(0) = 0. Ost<20 20 ASK YOUR TEACHER 10 O n 10 20 40 i(t) 50 30 20 ASK YOUR TEACHER 10 1 -2/04 dv dit t> 50 Watch It Ost <20 O Need Help? Read It t≥ 20 = mg -kv, 10 PRACTICE ANOTHER PRACTICE ANOTHER 20 30 30 40 40 t t Viewing Saved Work Revert to Last Response O where k >0 is a constant of proportionality. The positive direction is downward (a) Solve the equation subject to the initial condition v(0) = 0 v(t) = i (t) 50 40 30 20 10 i (t) 50 40 30 20 10 5 5 10 (0) Use the solution in part (a) to determine the limiting, or terminal, velocity of the mass. 10 15 15 MY NOTES 20 25 20 25 In (14) of Section 1.3 we saw that a differential equation describing the velocity v of a falling mass subject to air resistance proportional to the instantaneous velocity is 30 30 ASK YOUR TEACHER t (c) If the distance s, measured from the point where the mass was released above ground, is related to velocity v by ds/dt = v(t), find an explicit expression for s(t) if s(0) = 0. ОО s(t) =
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