Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to dothis by inspection, i.e. without much written computation.)A. S₁ = spanThe dimension of S₁ is6-21([-]-[3³³])|·10 35B. S₂ = spanThe dimension of S₂ isC. S3= span12The dimension of S3 isD. S4= span3 3·CH·H&HD−1 30 0The dimension of S4 isE. S5 = spanCHED-2(The dimension of S5 is37])-373-3324-15[[ ]]152-1513

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Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to do this by inspection, i.e. without much written computation.) 6 ([-] [3³])| 35 A. S₁ = span The dimension of S₁ is B. S₂ = span The dimension of S₂ is C. S3= span ([]][3][)) 0 -1 0 0 0 24 The dimension of S3 is

Each subspace below is the span of a collection of vectors. Find the dimension of each subspace by deleting linearly dependent vectors. (Try to do this by inspection, i.e. without much written computation.) 6 ([-] [3³])| 35 A. S₁ = span The dimension of S₁ is B. S₂ = span The dimension of S₂ is C. S3= span ([]][3][)) 0 -1 0 0 0 24 The dimension of S3 is

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter8: Applications Of Trigonometry

Section8.4: The Dot Product

Problem 48E

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