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- e teaching and le x .. Calendar m/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-... <ΔΗ° this question. Given the standard enthalpy changes for the following two reactions: X (1) 2Zn(s) + O2(g) → 2ZnO(s) (2) Zn(s) + Cl₂ (g) → ZnCl₂ (s) KJ + Submit Answer 8 more group attempts remaining what is the standard enthalpy change for the reaction: (3) 2ZnCl₂ (s) + O₂(g) → 2ZnO(s) + 2Cl₂ (g) ΔΗ° =? Retry Entire Group ΔΗ° - 696.6 kJ AH = -415.0 kJ == Previous NextI need step by step process solving [4.184x156(Tf-295)] + [4.184x85.2(Tf-368)] = 0. because my work is wrong. Thank you!!(d) 3-13. Distis me Jum 4 A method of analysis yields weights for gold that are low by 0.4 mg. Calculate the caused by this uncertainty if the weight of gold in the sample is (a) 900 mg. (c) 150 mg. 1-7. The method described in Problem 3-6 is to be used for the analysis of ores that assay about 1.2% gold. What minimum sample weight should be taken if the relative error resulting from a 0.4-mg loss is not to exceed -0.2%? percent relative error (a) (b) (b) 600 mg. (d) 30 mg. 3-14. Wha stan stam 3-15. Сог mea (b) -0.5%? (a) -0.8%? (c) (d) 1.2%? 3.5 3-8. The color change of a chemical indicator requires an overtitration of 0.04 mL. Calculate the percent relative error if the total volume of titrant is (a) 50.00 mL. (c) 25.0 mL. 3-9. A loss of 0.4 mg of Zn occurs in the course of an analysis to determine that element. Calculate the per- cent relative error due to this loss if the weight of Zn in the sample is (a) 40 mg. (c) 400 mg. 3.1 3.1 (b) 10.0 mL. 3.3 2.5 (d) 40.0 mL. Fo (a (E (b) 175…
- (i) (ii) (iii) (iv) 'I OMe HO H g H N Me Br SnMe3 OSiMe3 CHO OH NaNH, NH3 (1) Phl, Pd(PPH3)4 THF, reflux 1. Ph3P=CMe2 2. "Bu4NF 3. H30 + CH₂12, Zn C C₂H₂NO D C₁1H₁1N E C10H16O F C15H26O2-3 A 0.3202 (±0.0001) g sample of a pure monoprotic acid required 20.04 (±0.02) cm° of 0.1005 (±0.0005) mol dm neutralisation. Find the molar mass of the acid in g mol together with its uncertainty also in g mol, with an appropriate number of digits. NaOH for -1 Select one: a. 1.59 x 102+ 0.2 g mol b. 1.60 x 10 + 0.03 g mol C. 1.590 x 102 + 0.03 g mol d. 1.590 x 10- + 0.2 g mol 1.60 x 10-+0.2 g mol е. Clear my choiceV = (2a/x)'/4e¬ax², , =?
- (1) (1) (0) к ОН ОН - (її) ОН H₂SO4 heat PBr3 PBr3 (ii) он х ОН Br (i) OsO4; N (ii) NaHSO3; H20 PB13 POCI 3 (i) Li (ii) Cul Br (ii) Br ОН Mg, Et20 2 МСРВА ОН CuLi Na ОН 0 MgBr PB13 О O Na 2 С O Na Br combine carefully then H3O+ O 0 OH сохрасс CrO3 H₂SO4 =0 ОНthe chemical potential of a classical ideal gas is given by a) μ-kT In (πλ*) b) µ = }In(na®) c) µ = kgT ln(n²/3 2)3 d) µ = In(2!/32) =-In(n' e) all the above (a (b (c (d (e4. After correction for water conductivity, the conductivity of a 2.500 x 104 M aqueous solution of MGSO4 at 25°C was found to be 6.156 x 10-3 Sm1. Calculate Ke for the ion-pair-formation reaction Mg"(aq) + SO,?(aq) = M&SO4(aq) The molar ionic conductivities of Mg+ and SO42- ions in water are 0.0106 Sm?mol- and 0.0160 Sm²mol-, respectively.
- CHM019.2 Writing Ionic Equations(1).pdf - Foxit Reader O File Home Comment Fill & Sign View Form Protect Share Connect Help Q Tell me what you want to do.. Find O SnapShot Ô Fit Page TI T 89.44% A Link 0 File Attachment A Clipboard - «D Fit Width A Rotate Left A Bookmark G Image Annotation Hand Select Actual Reflow Typewriter Highlight D Fit Visible Rotate Right O Audio & Video Size Tools View Comment Links Insert Convert PDF 4 Word Start CHMO19.2 Writing Ioni... PDF 2 Word WRITING IONIC EQUATIONS I. Complete and balance the following equations. (1 pt each blank) 1. Molecular : РЬ(NO3):(aq) + K(ag) → KNO:(aq) + PbI2(s) Detailed ionic + Net ionic -> 2. Molecular : (NH4)3PO4(aq) + CacO:(s) → Cas(PO4)2(s) + (NH4)2CO3(aq) Detailed ionic Net ionic -> 3. Molecular : Ca(NO:)2(aq) + Hg2Iz(s) Hg2(NO3)2(aq) + Cal:(aq) Detailed ionic -> Net ionic + 4. Molecular : Cu(OH)2(s) + HCIO:(aq) → Cu(CIO:)2(aq) + H20() Detailed ionic -> + Net ionic + 5. Molecular : Mg(OH)2(s) + H2SO4(aq) → MgSO:(aq) +…C LOCH3 250 °C HBr }) m-CPBA MgBrDifferentiate acidimetry from alkalimetry