Draw the possible products of this epoxide ring-opening reaction. Use a dash or wedge bond to indicate the stereochemistry of substituents on asymmetric centers, where applicableIgnore any inorganic byproducts. 1) NaOH / H2O 2) dilute HCI Q
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- Draw the possible products of this epoxide ring-opening reaction. Use a dash or wedge bond to indicate the stereochemistry of substituents on asymmetric centers, where applicableIgnore any inorganic byproducts. 411 1) NaOH/H₂O 2) dilute HCIPlease fill in the missing reactants, reagents or products in the following reactions. Indicate relative stereochemistry where it is necessary CI j)Consider the mechanism for the reaction of cyclohexene and bromine at -5 °C in CCI,. The bromines in the equation are numbered to differentiate them in the mechanistic steps. 0. Identify the curved arrows needed for the mechanism, then draw the key intermediate and product. Clearly show stereochemistry, by drawing a wedge and dash bond at each chirality center (including hydrogen atoms). Draw one enantiomer for any racemates. CCI -5°C +Br,-Br₂ dibromocyclohexane A. Select the curved arrow(s) needed for step 1. A curved arrow starts from the lone pair of bromine 1 and points to an alkene carbon. Two curved arrows start on bromine 1, each pointing to an alkene carbon. A curved arrow starts from the alkene x bond and points to bromine 1. A curved arrow starts from the Br-Br bond and points to bromine 2. B. Draw 1 organic species and 1 inorganic species formed in step 1. Include charges and non-bonding electrons. Select Draw Rings More /Y C H Br Erase
- Draw chemical structure with appropiate stereochemistry ( cis or trans, E or Z)Name the structuresDraw the alkene that would react with the reagent given to account for the product formed. ? + H₂O H₂SO4 CH3 CH3CCH3 OH You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. Sn [F ChemDoodleⓇprovide the major profucts ( wrote "no reaxtion "if you think so) for the following reactions with correct stereochemistry. Please explain step by step with explanation
- Draw all stereoisomers formed in the reaction shown. Use wedges and dashes for tetrahedral stereogenic centers, if applicable. NH₂ HOAC2. Complete the following: Stereochemistry and regiochemistry may be important. type a) NaOH (aq) b) neutralize ➤ OMe a) LiAlH4, ether NMe2 f) b) H3O+ type b) a) HS SH ZnCl2, H+ b) Raney Ni g) type formation of thioacetal/desulfurization HO type Hell-Volhard-Zelinsky Reaction h) CO₂Et type Wittig Reaction H H₂N OEt OH DCC, CH2Cl2 Ph type a) NaH, THF CO₂Et d) b) BnBr, THE CO₂Et c) NaOH(aq); HCl(aq); heat type type HO type (COCI)2, cat DMF CH2Cl2 j) CI type a) NHEN b) LiAlH, THE c) H3O+ CO₂Me CO₂MeWhen a new center of chirality is created, isomers can result. For the reaction below, specify the kinds of isomers that are produced and in what ratio they form. (For reactions you are not already familiar with, products are shown without stereochemistry.) H₂C. Cl₂ Submit Answer The product(s) of this reaction is (are hv Retry Entire Group 2-chloroisomer(s) only a single achiral compound with no chiral centers a single meso compound a single chiral compound two achiral diastereomers in unequal amounts two enantiomers in equal amounts (a racemate) two enantiomers in unequal amounts two chiral diastereomers in equal amounts two chiral diastereomers in unequal amounts
- Draw the product of the reaction shown below. Use a dash or wedge bond to indicate stereochemistry of substituents on asymmetric centers, Ignore inorganic byproducts. Illo. Av DrawingStarting from the wedge-and-dash structure below (sighting down the indicated bond), rotate the back carbon to provide the structure in the conformation that will be capable of an E2 elimination. R/S stereochemistry is graded. # O H3C H Drawing > CI ||||| H Atoms, Bonds and Rings Tap a node to see sRearrangements can occur during the dehydration of 1° alcohols eventhough no 1° carbocation is formed—that is, a 1,2-shift occurs as the C—OH2+ bond is broken, forming a more stable 2° or 3° carbocation, asshown in Equation [1]. Using this information, draw a stepwisemechanism for the reaction shown in Equation [2]. We will see anotherexample of this type of rearrangement