Diskusi.4 Tuesday, 12 March 2024, 10:29 AM Hitung varian dari data berikut dengan cara koding. Hasil Ulangan Matematika Siswa Kl III SMP X Nilai Tugas Frekuensi (f) 61-65 6 66-70 10 71-75 25 76-80 34 81-85 24 86-80 12 91-95 7

How do I write a conclusion statement regarding which islands, if any, differ from one another with regard to the means of finch beak depths? I have images of my data attached

Please expalin?

3腾讯翻译君- 在线 X 9在线翻译_有道 MyMathLab Course -> A mathxl.com/Student/PlayerHomework.aspx?homeworkld%36055996038 …应用 M Gmail 9翻译君 O YouTube 四地图 翻译 XMathway | Aigebr. Math 95 - Fall '21 = Homework: HW 4 (Sec 2.3) Que Find the exact value of the remaining trigonometric functions of 0. cot 0 = cos 0>0 12 tan 0 =| (Simplify your answer, including any radicals. Use integers fractions any mbers in expression.) Enter your answer in the answer box and then click Check Answer, Help Me Solve This View an Example Get More Help -

4: Generat cuera 2. 3

Define Multicolinearity?

How to construct Scatterplot?

(13.3.11)

ata Set 12 “Passive and Active Smoke” in Appendix B includes cotinine levels measured in a group of nonsmokers exposed to tobacco smoke (n = 40, Mean = 60.58 ng>mL, s = 138.08 ng>mL) and a group of nonsmokers not exposed to tobacco smoke (n = 40, Mean = 16.35 ng>mL, s = 62.53 ng>mL). Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed by the body, cotinine is produced.  Use a 0.05 significance level to test the claim that nonsmokers exposed to tobacco smoke have a higher mean cotinine level than nonsmokers not exposed to tobacco smoke. 1.  Calculate the t test stastic using the following formula. 2.  Find the P value using Excel (i.e., =T.DIST.RT(t,df).  What is it? 3.  Compare the P-value to the signifcance level.  How do they compare?

ata Set 12 “Passive and Active Smoke” in Appendix B includes cotinine levels measured in a group of nonsmokers exposed to tobacco smoke (n = 40, Mean = 60.58 ng>mL, s = 138.08 ng>mL) and a group of nonsmokers not exposed to tobacco smoke (n = 40, Mean = 16.35 ng>mL, s = 62.53 ng>mL). Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed by the body, cotinine is produced.  Use a 0.05 significance level to test the claim that nonsmokers exposed to tobacco smoke have a higher mean cotinine level than nonsmokers not exposed to tobacco smoke. 1.  Find the degrees of freedom using the conversative estimate formula.  What is it? 2.  Find the critical value.  What is it? 3.  Sketch a normal distribution curve and highlight the region of significance.