Determine whether the following series converge. Justify your answer. 29 29 29 29 2.3 4.5 6.7 8.9 + O E. Let ak = + Let ak = Select the correct choice below and fill in the answer box to complete your choice. (Type an exact answer.) OA. The Ratio Test yields r = . This is less than 1, so the series converges by the Ratio Test. OB. The limit of the terms of the series is so the series converges by the Divergence Test. OC. The Ratio Test yields r = This is greater than 1, so the series diverges by the Ratio Test. O D. ak bk + 29 4K² + 2k 29 + ... 4K + 2k =1/1 2 and bk = and bk = 1 K² Since lim k→∞ Since lim ak , bk k→∞ = G = the series converges by the Limit Comparison Test. the series diverges by the Limit Comparison Test.

College Algebra
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Author:Jay Abramson
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Chapter9: Sequences, Probability And Counting Theory
Section: Chapter Questions
Problem 28RE: A ball has a bounce-back ratio 35 . of the height of the previous bounce. Write a series...
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Determine whether the following series converge. Justify your answer.
29 29 29 29
2.3 4.5
6.7 8.9
+
O E.
Let ak =
Select the correct choice below and fill in the answer box to complete your choice.
(Type an exact answer.)
OA. The Ratio Test yields r = . This is less than 1, so the series converges by the Ratio Test.
OB. The limit of the terms of the series is so the series converges by the Divergence Test.
This is greater than 1, so the series diverges by the Ratio Test.
OC. The Ratio Test yields r =
O D.
Let ak =
+
29
4K² + 2k
29
+ ...
4K + 2k
and bk =
and bk
=
1
k²
1
K²
Since lim
k→∞
Since lim
k→∞
ak
bk
ak
, bk
=
G
=
the series converges by the Limit Comparison Test.
the series diverges by the Limit Comparison Test.
Transcribed Image Text:Determine whether the following series converge. Justify your answer. 29 29 29 29 2.3 4.5 6.7 8.9 + O E. Let ak = Select the correct choice below and fill in the answer box to complete your choice. (Type an exact answer.) OA. The Ratio Test yields r = . This is less than 1, so the series converges by the Ratio Test. OB. The limit of the terms of the series is so the series converges by the Divergence Test. This is greater than 1, so the series diverges by the Ratio Test. OC. The Ratio Test yields r = O D. Let ak = + 29 4K² + 2k 29 + ... 4K + 2k and bk = and bk = 1 k² 1 K² Since lim k→∞ Since lim k→∞ ak bk ak , bk = G = the series converges by the Limit Comparison Test. the series diverges by the Limit Comparison Test.
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