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Determine the general/particular solution (whichever applies): (D²+1)y=x²+1, y(0) = 5, y(1) = 0 y=2cos (x) - 6cot (1) sin(x) + x² + 3 y=6cos y = 6cos (x) - 6cor (1) sin(x) + x²-1 y=4cos(x) - 4cor (1) sin(x) + 3x² - 4x + 1 (x) - 6cor (1) sin(x) + 2x2-x-1

Determine the general/particular solution (whichever applies): (D²+1)y=x²+1, y(0) = 5, y(1) = 0 y=2cos (x) - 6cot (1) sin(x) + x² + 3 y=6cos y = 6cos (x) - 6cor (1) sin(x) + x²-1 y=4cos(x) - 4cor (1) sin(x) + 3x² - 4x + 1 (x) - 6cor (1) sin(x) + 2x2-x-1

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.2: Partial Derivatives
Problem 28E
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Determine the general/particular solution (whichever applies): (D²+1)y=x²+1, y(0) = 5, y(1) = 0 y=2cos (x) - 6cot (1) sin(x) + x² + 3 O y=6cos y = 6cos (x) - 6cor (1) sin(x) + x²-1 y=4cos(x) - 4cor (1) sin(x) + 3x² - 4x + 1 (x) - 6cor (1) sin(x) + 2x2-x-1
Transcribed Image Text:Determine the general/particular solution (whichever applies): (D²+1)y=x²+1, y(0) = 5, y(1) = 0 y=2cos (x) - 6cot (1) sin(x) + x² + 3 O y=6cos y = 6cos (x) - 6cor (1) sin(x) + x²-1 y=4cos(x) - 4cor (1) sin(x) + 3x² - 4x + 1 (x) - 6cor (1) sin(x) + 2x2-x-1
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