Derive the deflection at different points of the beam, as shown in the table. Use MOMENT AREA METHOD B * 8 = (10L² – 10L²X+ 5Lx² – xr) 120L EI A
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- A beam ABC is fixed at end A and supported by beam DE at point B (sec figure). Both beams have the same cross section and are made of the same material. Determine all reactions due to the load P. What is the numerically largest bending moment in cither beam?Calculate the beam deflection at point C. E = 206.8 GPa, I„ = 1.873 x 10-6 mª. Use either the double integration method or the moment area method. Show your work. 200 N 500 N 50.8 mm -------z 76.2 mm A 1 m 1 m 2 mCalculate the support reaction at A and B for thve beam shown in the fiqure below Take F 700 N. 3M 1M By Reaction force at point B By UN. Reaction force at point A N. Ay=
- 1. The figure shows Beam Diagram 3 provided by CISC Handbook of Steel Construction, where W=total applied load in kN. (1) using 4th-order differential equation to obtain the deflection equation y (i.e., Ar) for interval 0G.) Solve for the angle at the hinge support and the deflection at point C. El=20000KN-m2. Use Area-Moment Method 10 KN /m 20kN 20 kN C Im 1-5m ImHi, I want to find the location on the beam where the maximum bending moment happens as measured from point A. I have already gathered the following information. FAx= 0 FAy= 25.0869 FCy= 32.913 the sheer force at B= 3.087 The bending moment at B = 77.4785 Let the loading coefficents be: W1 = 4 kN/m, W2 = 8 kN/m Let the lengths be: L1 = 5.5m , L2 = 6m. If anyone could help me with this last step of the problem that would be great.The second integration of bending moment equation will give slope of the beam. Select one: O True OFalse3. Find the beam deflection y(x) that satisfies El = W (x) for 0For the beam and loading shown, use discontinuity functions to compute: (a) the deflection VA of the beam at A, and (b) the deflection Vmidspan of the beam at midspan (i.e., x = 2.45 m). Assume a constant value of El = 1270 kN-m² for the beam; M₁ = 9 kN-m, wo = 19.8 kN/m, LAB = 1.1 m, LBc = 2.7 m. MA A Answer: (a) VA = (b) Vmid i LAB i Wo B LBC mm. mm.Derive the deflection at different points of the beam, as shown in the table. Use CONJUGATE BEAM METHOD. Wo wo.x? (6L² – 4Lx+ x²) 24EI BFor the beam shown, use only singularity functions. V₁ = 45 lbf/in and V/₂ = 5 in. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 0 1400 lbf Hinge JA B₁ C R₂ R₁ 4 in 4 in 2 in V1 V2 D R₂ + What is the value of the peak moment between points Cand D? The peak moment between points C and Dis Ibf.in.The simply supported beam carries a uniformly distributed load over parts of its length. Compute (a) the midspan slope and deflection, (b) the slope and deflection at point C. Segment AC’s beam property is worth EI and segment BC’s beam property is worth 2EI. E = 200 GPa, I = 80x106 mm4. Solve problem using the Area Moment Method.SEE MORE QUESTIONSRecommended textbooks for youMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning