Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH=1. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) OH HO Ostable of Ounstable OH Ostable Ounstable Ostable Ounstable O stable Ounstable : G Π P alo.
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- Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH=12. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) HO ☑ O stable OH stable Ounstable unstable OH O stable O unstable stable unstable GDecide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 2. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) OH Ostable O unstable O stable O unstable OH OH u Ostable O unstable O stable O unstable 0 AJ :0 Ahm X trDecide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 1. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) OH O stable O unstable OH X 5 O stable O unstable O stable O stable O unstable OH O unstable OH
- Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 2. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) e OH stable O unstable stable O unstable OH OH ge O stable O unstable O stable O unstable 0:0 X +7Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH=2. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) OH OH HO Ostable Ounstable O stable Ounstable HO Click and drag to start drawing a structure. stable Ounstable O stable Ounstable ☐ X 口: G EX oloG Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 11. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) X OH Ostable Ostable Ounstable Ounstable OH OH Ostable Ounstable stable Ounstable [H ח' :0 X G
- Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 2. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) OH OH Ostable Ounstable Ostable unstable Ostable Ounstable OH 15 OH Ostable Click and drag to start drawing a structure. Ounstable O '7 X 0:0 X to SUsing the table of bond dissociation energies, the AH for the following reaction is CH4 + 20 2→ CO 2 + 2 H2O Bond D (kJ/mol) C-H 413 O=O 495 =0 799 463 -52 154 -1246 684 -808 kJ.CO₂H -OH -OH heat 1. SOCI 2, A 2. NaO,CCH2CH3 ?
- Molecules must (absorb, liberate) energy to break theirbonds and (absorb, liberate) energy when their bonds arereformed.What is a triplet state? Are there molecules that have a triplet base state?Based on relative bond strengths, classify these reactions as Endothermic Exothermic endothermic (energy absorbed) or exothermic (energy released). Strongest bond А-В А-А В-В C-C В-С А-С Weakest bond Answer Bank AB + C → AC + B А + ВС — АВ + С В, + С, — 2 ВС A, + B, → 2 AB Аз + C, — 2 АС