Date: Class: nich the parabola axis is UTION tok -8 -8 -S y dr 4 q у x-intercepts NO SOLUTION # 4. 5. 6. m Solutions: THE DISCRIMINANT EXAMPLES Use the discriminant to determine the number of solutions. m 4. y=x²-10x+16 5. y = -x² +9 6. y = -3x² + 6x Formula: D "d=b²-4ac a b с 7. y = x +5x+4 m X X 2 solutions 01 solution d=5²³-4(1)(1) a solutions O 25-16 9. y = x² +10x + 25 y y y > #td> 0. then there are >it de 0, then there are > ltd <0, then there are 2 solutions. 1 solutions. solutions. 8. y=x²-3x+10 d = (-3) ²= 4(1)(108 |d= 9-40=-31 d=9 2 solutions 10. y = 2x² - 4x-3 1 solution O solutions O2 solutions 1 solution O solutions O2 solutions 1 solution 0 solutions

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.6: Multiplying Polynomials
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Question
Date:
Class:
nich the parabola
axis
is
UTION
tok
-8
-8
-S
y
dr
4
q
у
x-intercepts
NO SOLUTION
#
4.
5.
6.
m
Solutions:
THE
DISCRIMINANT
EXAMPLES
Use the discriminant to
determine the number
of solutions.
m
4. y=x²-10x+16
5. y = -x² +9
6. y = -3x² + 6x
Formula:
D
"d=b²-4ac
a b
с
7. y = x +5x+4
m
X
X
2 solutions
01 solution
d=5²³-4(1)(1) a solutions
O
25-16
9. y = x² +10x + 25
y
y
y
> #td> 0. then there are
>it de 0, then there are
> ltd <0, then there are
2 solutions.
1 solutions.
solutions.
8. y=x²-3x+10
d = (-3) ²= 4(1)(108
|d= 9-40=-31
d=9
2 solutions 10. y = 2x² - 4x-3
1 solution
O solutions
O2 solutions
1 solution
O solutions
O2 solutions
1 solution
0 solutions
Transcribed Image Text:Date: Class: nich the parabola axis is UTION tok -8 -8 -S y dr 4 q у x-intercepts NO SOLUTION # 4. 5. 6. m Solutions: THE DISCRIMINANT EXAMPLES Use the discriminant to determine the number of solutions. m 4. y=x²-10x+16 5. y = -x² +9 6. y = -3x² + 6x Formula: D "d=b²-4ac a b с 7. y = x +5x+4 m X X 2 solutions 01 solution d=5²³-4(1)(1) a solutions O 25-16 9. y = x² +10x + 25 y y y > #td> 0. then there are >it de 0, then there are > ltd <0, then there are 2 solutions. 1 solutions. solutions. 8. y=x²-3x+10 d = (-3) ²= 4(1)(108 |d= 9-40=-31 d=9 2 solutions 10. y = 2x² - 4x-3 1 solution O solutions O2 solutions 1 solution O solutions O2 solutions 1 solution 0 solutions
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