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- E' I с E 1. Phenylamine is an aromatic amine that is used in the manufacture of dyes. When absorbed through the skin it causes the Fe+2 in hemoglobin to become oxidized into Fe+3, resulting in the formation of methemoglobin which cannot bind to or transport oxygen. Phenylamine is soluble in water and acts as a weak base. a. a. CøHşNHz (aq) + H2O (l) = CHşNH;* (aq) + OH (aq) When you measure the concentrations of the ionized substances you find them to be: [C6H5NH₂] = 0.234 mol/L [C6H5NH3*] = 2.8 x 10³ mol/L [OH-]= 2.8 x 10³ mol/L If the K is 4.27 x 10-10, is the reaction at equilibrium? If not, which direction does it need to move (right or left) to reach equilibrium? Explain. At equilibrium the concentrations of the ionized substances are: [C6H5NH₂] = 0.0537 mol/L [C6H5NH3*] =4.79 x 10€ mol/L [OH-]= 4.79 x 10¹ mol/L If this reaction is taking place in a 2.0L container, and 1.5 moles of phenylamine were added to the reaction, what will the new concentrations of the three ionic species…1. NAOH, H2O 2. H300 i. NaOEt ii. MeBr 3. heat Ph OEtE' I U E 1. Phenylamine is an aromatic amine that is used in the manufacture of dyes. When absorbed through the skin it causes the Fe*2 in hemoglobin to become oxidized into Fe*³, resulting in the formation of methemoglobin which cannot bind to or transport oxygen. Phenylamine is soluble in water and acts as a weak base. a. a. C6H5NH2 (aq) + H₂O (l) C6H5NH3* (aq) + OH- (aq) When you measure the concentrations of the ionized substances you find them to be: [C6H5NH₂] = 0.234 mol/L [C6H5NH3*] = 2.8 x 10-5 mol/L [OH-]= 2.8 x 10-5 mol/L If the Kb is 4.27 x 10-10, is the reaction at equilibrium? If not, which direction does it need to move (right or left) to reach equilibrium? Explain. At equilibrium the concentrations of the ionized substances are: [C6H5NH₂] = 0.0537 mol/L [C6H5NH3*] = 4.79 x 106 mol/L [OH-]= 4.79 x 10¹6 mol/L If this reaction is taking place in a 2.0L container, and 1.5 moles of phenylamine were added to the reaction, what will the new concentrations of the three ionic…
- a. I 15.0 ml of H:SO.are required to neutralize 25.0 ml of 0.660 N KOH solutton, to what volume should 100 mL of the acid be diluted with water in order for the resulting solution to be 0.5 N? What volume of 1.00 N NaOH should be added to a liter of the KOH in order for the resulting solution to be 0.700 N as a base? What volume of the diluted acid be neutraized by 25.1 ml of the alkali 2. b. c. mixture?HH H₂O H₂SO4 Br 1) NaH d Br 1) BH3 2) H₂O₂ NaOH Br f NaNH, excess DMSO h 1) 2) Br Br10A Complete the figure below. Br NaCN DMSO B A NH₂ C 1. Br₂, NaOH 2. H₂O/H* TT. H₂SO4