(d) Find the area under the curve that lies to the left of z = 1.46. The area is (Round to four decimal places as needed.) (e) Find the area under the curve that lies to the right of z = -0.78. The area is (Round to four decimal places as needed.) (f) Find the area under the curve that lies between z = -0.42 and z = 1.89. The area is (Round to four decimal places as needed.)
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- Find the value of z if the area under a standard normal curve (a) to the right of z is 0.3228; (b) to the left of z is 0.1271; (c) between 0 and z, with z> 0, is 0.4890; and (d) between -zand z, with z> 0, is 0.9500. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.A simple random sample of size n is drawn. The sample mean, x, is found to be 18.2, and the sample standard deviation, s, is found to be 4.5. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about u if the sample size, n, is 35. Lower bound: ; Upper bound: (Use ascending order. Round to two decimal places as needed.)Areas under the Normal Curve .00 .01 .02 .01 .02 .03 .04 .05 .06 .07 .08 -3.4 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0002 -3.4 -3.3 0.0005 0.0005 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0003 -3.3 -3.2 0.0007 0.0007 0.0006 0.0006 0.0006 0.0006 0.0006 0.0005 0.0005 0.0005 -3.2 -3.1 0.0010 0.0009 0.0009 0.0009 0.0008 0.0008 0.0008 0.0008 0.0007 0.0007 -3.1 -3.0 0.0013 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.0010 0.0010 -3.0 -2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 -2.9 -2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 -2.8 -2.7 0.0035 0.0034 0.0033 0.0032 0.0031 0.0030 0.0029 0.0028 0.0027 0.0026 -2.7 -2.6 0.0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 0.0036 -2.6 -2.5 0.0062 0.0060 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048 -2.5 -2.4 0.0082 0.0080 0.0078 0.0075 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064 -2.4 -2.3 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094…
- Areas under the Normal Curve .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.5040 0.5438 0.5832 0.5199 0.5596 0.5239 0,5636 0.6026 0.5279 0,5675 0.6064 0.0 0.5000 0.5080 0.5120 0.5319 0.5714 0.6103 0.5160 0.5359 0.0 0.5753 0.1 0.2 0.5398 0.5478 0.5517 0.5557 0.1 0.5793 0.5871 0.5910 0.5948 0.5987 0.6141 0.2 0.6331 0.6700 0.6368 0.6480 0.6517 0.6879 0.6179 0.6217 0.6255 0.6628 0.6293 0.6664 0.6406 0.6443 0.6808 0.3 0.4 0.3 0.4 0.6554 0.6591 0.6736 0.6772 0.6844 0.6985 0.7324 0.7642 0.7224 0.7549 0.7852 0.5 0.6915 0.6950 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.5 0.6 0.7257 0.7291 0.7357 0.7389 0.7422 0.7734 0.7454 0.7486 0.7794 0.8078 0.7517 0.7823 0.6 0.7 0.7580 0.7611 0.7673 0.7704 0.7764 0.7 0.7995 0.8264 0.7939 0.8 0.9 0.8051 0.8315 0.8133 0.8389 0.7881 0.7910 0.7967 0.8023 0.8106 0.8 0.8159 0.8186 0.8212 0.8238 0.8289 0.8340 0.8365 0.9 1.0 0.8413 0.8485 0.8554 0.8770 0.8962 0.8599 0.8810 0.8438 0.8461 0.8508 0.8531 0.8577 0.8621 1.0 1.1 0.8643 0.8665 0.8686 0.8708 0.8830 0.8729 0.8925…Assume that adults have lQ scores that are normally distributed with a mean of µ = 105 and a standard deviation g = 15 Find the probability that a randomly selected adult has an IQ between 88 and 122. Click to view page 1 of the table Click to view page 2 of the table. ... The probability that a randomly selected adult has an IQ between 88 and 122 is (Type an integer or decimal rounded to four decimal places as needed.)To test Ho = 105 yersus H₁: #105 a simple random sample of size n = 35 is obtained. Complete parts a through e below. Click here to view the t-Distribution Area in Right Tail. (a) Does the population have to be normally distributed to test this hypothesis? Why? A. Yes, because n ≥ 30. B. Yes, because the sample is random. C. No, because n ≥ 30 OD. No, because the test is two-tailed. (b) If x= 102.0 and s=5.7, compute the test statistic. The test statistic is to = (Round to two decimal places as needed.) ...
- Find the area to the left of z = -1.5 Solution: Draw the normal curve and shade the required region 2 3 Find the area that z = -1.5 corresponds to an area corresponds to the z-value Examine the graph and use probability notation to form the equation . The proportion of the area to the left of z = -1.5 is7. Find the area under the standard normal curve between (-1.35) and the mean?Determine the area under the standard normal curve that lies to the left of (a) Z=1.64, (b) Z=0.14, (c) Z=-1.61, and (d) Z=0.04. Click the icon to view a table of areas under the normal curve. (a) The area to the left of Z= 1.64 is (Round to four decimal places as needed.) View an example Get more help - OLDC Tables of Areas under the Normal Curve (7 -0.0 0.0 -KI U.4002 04302 UA322 0.4483 0.4493 09404 04304 UA32J UAZOO URAT 0.5000 0.4960 0.4920 0.4880 0.4880 0.4840 0.4801 0.4761 0.4721 0.4681 0.4641 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 05239 0.5279 0.5319 0.5359 0.1 0.5398 0.5438 0.5478 0.5517 05557 0.5596 0.5636 0.5675 05714 0.5753 0.2 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141 0.3 0.6179 0.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517 0.4 0.6554 0.6591 0.6628 0.6664 0.6700 0.6736 0.6772 0.6808 0.6844 0.6879 0.5 0.6915 0.6950 0.6985 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.7224 0.6 0.7257 0.7291 0.7324 0.7357 0.7389 0.7422 0.7454…
- Determine the area under the standard normal curve that lies between (a) Z=-1.55 and Z=1.55, (b) Z=-1.14 and Z=0, and (c) Z=0.13 and Z=2.22. Click the icon to view a table of areas under the normal curve. olve this P (a) The area that lies between Z=-1.55 and Z=1.55 is (Round to four decimal places as needed.) View an example 4x IA Get more help - F4 LDC 0 Tables of Areas under the Normal Curve Area F7 PrtScnfa F8 TABLE V 2 .00 .08 -3.4 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0002 -3.3 0.0005 0.0005 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0003 -3.2 0.0007 0.0007 0.0006 0.0006 0.0006 0.0006 0.0006 0.0005 0.0005 0.0005 -3.1 0.0010 0.0009 0.0009 0.0009 0.0008 0.0008 0.0008 0.0008 0.0007 0.0007 -3.0 0.0013 0.0013 0.0013 0.0012 0.0012 0.0011 00011 00011 0.0010 0.0010 -2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 -2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 -2.7 0.0035 0.0034 0.0033 0.0032 0.0031…Find the indicated probability using the standard nomal distribution. P(z<-0.07) Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. P(z< -0.07) = (Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer. Help Me Solve This View an Example Get More Help - MaFind the indicated area under the standard normal curve. Between z= -2.81 and z =2.81 Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. The area between z= -2.81 and z= 2.81 under the standard normal curve is. (Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer. Help Me Solve This View an Example Get More Help -