CS₂ H₂O = s=c=s H-O-H A^4 sp AX₂ sp³ AX₂E₂ tetrahedral linear linear tetrahedral bent 180° ~109.5° no polar bonds, so no molecular polarity S=C=S

Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter8: Advanced Theories Of Covalent Bonding
Section: Chapter Questions
Problem 40E: Predict the valence electron molecular orbital configurations for the following, and state whether...
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Molecule or
Polyatomic
CHzCl
2-
Co₂²
CH4
CS₂
H₂O
Lewis structure
H-C-CI:
H
H
H-C-H
H
s=c=s
H–O–H
2-
Hybrid-
ization
AXE
3
sp³
AX4
2
sp²
AX3
3
sp³
AX4
sp
AX2
3
sp³
AX₂E2
Electron pair geometry
Molecular shape
tetrahedral
tetrahedral
trigonal planar
trigonal planar
tetrahedral
tetrahedral
linear
linear
tetrahedral
bent
Bond angles
all ~109.5°
all 120°
all ~109.5°
180°
~109.5°
Bond
Polarity
H
C
2.5 2.1
Cl
2.5 3.0
CO
2.5 3.5
C-H
2.5 2.1
Molecular Polarity
if the molecule is polar, add a dipole arrow
if not polar, state so and why
H
H
H
i
no molecular polarity because of shape
CI
H
H
HC
H
no polar bonds, so no molecular polarity
H
S=C=S
H
Transcribed Image Text:Molecule or Polyatomic CHzCl 2- Co₂² CH4 CS₂ H₂O Lewis structure H-C-CI: H H H-C-H H s=c=s H–O–H 2- Hybrid- ization AXE 3 sp³ AX4 2 sp² AX3 3 sp³ AX4 sp AX2 3 sp³ AX₂E2 Electron pair geometry Molecular shape tetrahedral tetrahedral trigonal planar trigonal planar tetrahedral tetrahedral linear linear tetrahedral bent Bond angles all ~109.5° all 120° all ~109.5° 180° ~109.5° Bond Polarity H C 2.5 2.1 Cl 2.5 3.0 CO 2.5 3.5 C-H 2.5 2.1 Molecular Polarity if the molecule is polar, add a dipole arrow if not polar, state so and why H H H i no molecular polarity because of shape CI H H HC H no polar bonds, so no molecular polarity H S=C=S H
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