Create a class Circle to compute area and circumference using Java
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- Java Programming Create a program that computes the perimeter of a square, rectangle and the circumference of a circle using interface.Java: Design the class Circle that can store the radius and the center of the circle based on the class Point we talked in the class. You should be able to perform the usual operation on a circle, such as setting radius, printing the radius, calculating and printing the area and circumference, and carrying out the usual operations on the center. Here is the code: public class Point {public static void main(String[] args) { } protected double x, y; // coordinates of the Point //Default constructorpublic Point(){setPoint( 0, 0 );} //Constructor with parameterspublic Point(double xValue, double yValue ){setPoint(xValue, yValue );} // set x and y coordinates of Pointpublic void setPoint(double xValue, double yValue ){x = xValue;y = yValue;} // get x coordinatepublic double getX(){return x;} // get y coordinatepublic double getY(){return y;} // convert point into String representationpublic String toString(){return "[" + String.format("%.2f", x)+ ", " + String.format("%.2f", y) + "]";}…Need dry run for the following code in java language This question is from the book absolute java 5th edition by savitch w mock k Ch 13 question 10
- please help me with the following 1) make a sierpenski triangle using java and recursion. Make it similar to the code below. And please comment the code 2) Please make the follow code out put on the console. It a t square fractal import java.awt.image.*;import java.awt.Color;import java.io.*;import javax.imageio.*; public class Main{ static final int DIMENSION = 1000; static BufferedImage image = new BufferedImage(DIMENSION, DIMENSION, BufferedImage.TYPE_INT_RGB); static final int WHITE = Color.WHITE.getRGB(); static final int BLACK = Color.BLACK.getRGB(); private static void drawSquare(int x, int y, int side) { if (side <= 0) return; else { int left = x - side/2; int top = y - side/2; int right = x + side/2; int bottom = y + side/2; for (int i = left; i < right; i++) for (int j = top; j < bottom; j++) { image.setRGB(i, j, BLACK); }…Java - Encapsulation A rectangle can be formed given two points, the top left point and the bottom right point. Assuming that the top left corner of the console is point (0, 0), the bottom right corner of the console is point (MAX, MAX) and given two points (all “x” and “y” coordinates are positive), you should be able to draw the rectangle in the correct location, determine if it is a square or a rectangle, and compute for its area, perimeter and center point. To be able to do this, you should create a class Point (that has an x-coordinate and a y-coordinate). Also, create another class called Rectangle. The Rectangle should have 2 points, the top left and the bottom right. You should also implement the following methods for the Rectangle: display() - draws the rectangle on the console based on the samplearea() - computes and returns the area of a given rectangleperimeter() - computes and returns the perimeter of a given rectanglecenterPoint() - computes and returns the center point…Java programming question: Complete the missing blank of code given by the picture below.
- Note: Please Answer in java only Ron has a very good knowledge of graphs and relationships. So he is given a question to solve it using a programming language. The coordinates of centres of these squares are (x1, a/2), (x2, a/2) and (x3, a/2) respectively. All of them are placed with one of their sides resting on the x-axis. You are allowed to move the centres of each of these squares along the x-axis (either to the left or to the right) by a distance of at most K. Find the maximum possible area of intersections of all these three squares that you can achieve. That is, the maximum area of the region which is part of all the three squares in the final configuration. Input 1 10 123 Output 0.00000#Write your class code here using python print("Box 1")b1 = box([10,10,10])print("=========================")print("Height:", b1.height)print("Width:", b1.width)print("Breadth:", b1.breadth)print("-------------------------")print("Box 2")b2 = box((30,10,10))print("=========================")print("Height:", b2.height)print("Width:", b2.width)print("Breadth:", b2.breadth)b2.height = 300print("Updating Box 2!")print("Height:", b2.height)print("Width:", b2.width)print("Breadth:", b2.breadth)print("-------------------------")print("Box 3")b3 = b2print("Height:", b3.height)print("Width:", b3.width)print("Breadth:", b3.breadth)T/F 1. Java methods can only return primitive types