Counter-Controlled Loops for (count = 1; count <= 10; count++) for count in [2, 4, 6]: print count Ans: ___________________
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Counter-Controlled Loops
for (count = 1; count <= 10; count++)
for count in [2, 4, 6]:
print count
Ans: ___________________
Step by step
Solved in 2 steps
- C++ Coding: Nested Loops Create a constant DIM. Set DIM to 7, and use a nested loop to display the following square matrix output. Output Example: - - - X - - -- - - X - - -- - - X - - -X X X O X X X- - - X - - -- - - X - - -- - - X - - -(Numerical) Write a program that tests the effectiveness of the rand() library function. Start by initializing 10 counters to 0, and then generate a large number of pseudorandom integers between 0 and 9. Each time a 0 occurs, increment the variable you have designated as the zero counter; when a 1 occurs, increment the counter variable that’s keeping count of the 1s that occur; and so on. Finally, display the number of 0s, 1s, 2s, and so on that occurred and the percentage of the time they occurred.Write the following for loop as a while loop. for (int count = 1; count <= 10; count++) cout << count << endl ;
- The While loop is a --------------- type of LoopHhe Ocut put of beollowing C- Poogsam write Loop Count =Y + 3 :.Y= 6 #include void main o Counter = 12; // ini tialige Countes int loop Count = Y+ 3 ; %3D while (courmter s Loop Count) printf (“ Countes = %-d\n", counter), Countes = Counter -1; i4 (counter ! = 9) point s (" Not Grood. In'"); else points (" G0od. !!! m."):Please help convert this for loop into while loop:
- Assignment for Computer Architecture: N Factual by Recusion *please have comments in the code* You are to write a program in MIPS that computes N! using recursion. Remember N! is the product of all the numbers from 1 to N inclusive, that is 1 x 2 x 3 x (N – 1) x N. It is defined as 1 for N = 0 and is undefined for values less than 0. The programs first requests the user to input the value of N (display a prompt first so the user knows what to do). If the input value is less than 0, the program is to display “N! undefined for values less than 0” and then requests the user to input the value of N again. If the value input is non-negative, it is to compute N! using a recursive function, that is one that calls itself. You are to have your name, the assignment number, and a brief description of the program in comments at the top of your program. Since this is an assembly language program, I expect to see comments on almost every line of code in the program. Also make the…function main() { # ist: input numbers #w: outer for loop index # X: inner for loop index # y: number of parsmeters # min: index for max value at the time of iteration # buf: used for swapping ____________________a _______ #declare local vars let=___________b___ #intialize aary with the parametrs y= _______c___ # find the lenght of lstfor((________________)); do min=________e_____ # intialize main index for ((___________f_______)); do # find index for main value in one line. use a short tets. _________g_____done # swap- two values using two indices, min and outerloop # use buf to hold value when swapping ________________h________ # move min lst [.] to buf ________________i_______ # move lst[.] to lst[.] _________________j_____ # move buf to lst[.]done}main "@" # pass the input parameters to the function main# end of bash script show me the ss when u run chatgpt doesnt give right code2- The factorial n! of a positive integer n is defined as n! = 1*2*3 . .. * (n-1) * n Where 0! = 1 Write a function to calculate the factorial of a number. Argument: A number n of type unsigned int. Returns: The factorial n! of type long double. Write two versions of the function, where the factorial is • calculated using a loop calculated recursively Test both functions by outputting the factorials of the numbers 0 to 20.
- main.c + c Test Cases Executions 3. Negative Fusion by CodeChum Admin 1 E Run Tests As l've said before, there are three types of numbers: the positive, the zero, and the negative ones. Today, we shall pay attention only to the negative ones now. Make a loop that will accept O Test Case 1 random decimal/float numbers. When the user Your Output inputs 0, the loop will terminate and then output No Output the sum of all negative numbers inputted in 3 decimal places. Expected Output Let's code this. Enter a number: 2.4434 Enter a number: -1.3433 Input Enter a number: -2.444 Enter a number: 6.432 1. A series of decimal numbers Enter a number: 0 Sum of all negatives = -3.787 Output The first lines will contain message prompts to input the decimal numbers. The last line contains the sum of all negative numbers with 3 decimal places. O Test Case 2use while loop instead of for loopHelp me to make flowchart for my python code. ############################## import random def binary_search(arr, low, high, m): ----if high >= low: --------mid = (high + low) // 2 --------if arr[mid] == m: ------------return mid --------elif arr[mid] > m: ------------return binary_search(arr, low, mid - 1, m) --------else: ------------return binary_search(arr, mid + 1, high, m) ----else: --------return -1 L = []a = random.randint(5,10)b = random.randint(5,10)for i in range (0,a): ----L.append('D')for i in range(0,b): ----L.append('R')output = binary_search(L,0,len(L)-1,'R')if output != -1: ----print("index of the first visitor", str(output)) else: ----print("index of the others visitor")
