Convert the fol lowing trancfer functions into its difference equation. 2-1 H(2) = 13z+ 0.36 Solution: a. Dividing the numerator and denominator by z? to obtain the transfer function whose numerator and denominator polynomi als have the negative power of z, it follows that (22-1)/ -13z+036)/ 1-72 H(2) = 1+13r 0.36z Yiz) X(2) 1-2 1+13z+036z Y(2)(1+13z1+0.36z) - X(z)(1-z2) Y(Z) +13z Y(2) +0 36z 2Y(z) = X(2)-z x(z) y(n) +13y(n- 1) +036yn - 2) = x(n) - x(n -2) y(n) - x(n) – x(n - 2) - 1.3y(n - 1)-0.36y(n- 2) H.W1: Draw the system which is expressed in the above difference equation.
Convert the fol lowing trancfer functions into its difference equation. 2-1 H(2) = 13z+ 0.36 Solution: a. Dividing the numerator and denominator by z? to obtain the transfer function whose numerator and denominator polynomi als have the negative power of z, it follows that (22-1)/ -13z+036)/ 1-72 H(2) = 1+13r 0.36z Yiz) X(2) 1-2 1+13z+036z Y(2)(1+13z1+0.36z) - X(z)(1-z2) Y(Z) +13z Y(2) +0 36z 2Y(z) = X(2)-z x(z) y(n) +13y(n- 1) +036yn - 2) = x(n) - x(n -2) y(n) - x(n) – x(n - 2) - 1.3y(n - 1)-0.36y(n- 2) H.W1: Draw the system which is expressed in the above difference equation.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Question
![Dr. Mohamad Alhabbar
Digital Signal Processing
Ninevah University
Communication Engineering Department
College of Electronics Engineering
Example
Convert the fol lowing tracfer functions into its di fference equation.
2-1
H(2) = 7+13z+0.36
Solution:
a. Dividing the numerator and denominator by z? toobtain the trasfer function whose numerator and denominator
polynomi als have the negative power of z, it follows that
(22-1)/2
(F-137+036)/
1-72
H(2) =
1+13z +0.36z 2
Y(z)
X(Z)
1-z 2
1-1 3z+0367
Y(2)(1+13z1+0.36z ) = X(z)(1-z 2)
Y(2) + 13z Y(2) +0 36z 2Y(z) X(2)- z x(z)
y(n) +13y(n- 1) +036yn- 2) = x(n) - x(n - 2)
y(n) = x(n) – x(n- 2) - 13y(n - 1) -0.36y(n - 2)
H.W1: Draw the system which is expressed in the above difference equation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe7735f33-8190-4463-a009-8b6a4699c004%2F7df71c69-8499-4297-beee-3b57b07c042f%2F6ec44nq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Dr. Mohamad Alhabbar
Digital Signal Processing
Ninevah University
Communication Engineering Department
College of Electronics Engineering
Example
Convert the fol lowing tracfer functions into its di fference equation.
2-1
H(2) = 7+13z+0.36
Solution:
a. Dividing the numerator and denominator by z? toobtain the trasfer function whose numerator and denominator
polynomi als have the negative power of z, it follows that
(22-1)/2
(F-137+036)/
1-72
H(2) =
1+13z +0.36z 2
Y(z)
X(Z)
1-z 2
1-1 3z+0367
Y(2)(1+13z1+0.36z ) = X(z)(1-z 2)
Y(2) + 13z Y(2) +0 36z 2Y(z) X(2)- z x(z)
y(n) +13y(n- 1) +036yn- 2) = x(n) - x(n - 2)
y(n) = x(n) – x(n- 2) - 13y(n - 1) -0.36y(n - 2)
H.W1: Draw the system which is expressed in the above difference equation.
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